You say that there is uniform acceleration so:
vf-vi=at (final velocity minus initial velocity is equal to acceleration times time)
We know vf, vi, and t so we can solve for acceleration:
24-12=a10
12=10a
a=1.2
That is the acceleration, we will need to integrate with respect to time twice...
v=⌠a dt
v=at+vi , we know a=1.2m/s^2 and vi=12m/s
v=1.2t+12,
x=⌠1.2t+12 dt
x=1.2t^2/2+12t+xo, we can just let xo=0 for this problem...
x(t)=0.6t^2+12t
Now we know that this acceleration lasts for 10 seconds so the distance traveled in that time is:
x(10)=0.6(10^2)+12(10)
x(10)=60+120
x(10)=180 meters
it literally gave you the equation lol
y= 6x + 1/2
Answer:
-20
Step-by-step explanation:
(r + b − g)(b + g)
we have fom statement:
r = 9
b = 5
g= −6
so we have:
(r + b − g)(b + g)= (9+5-(-6))*(5+(-6))
(r + b − g)(b + g)= (14+6)*(-1)
(r + b − g)(b + g)= -20
Answer: the third one
Step-by-step explanation: bcuz I’m Albert instine ;)
Answer:
Step-by-step explanation:
- Let the denominator be x
- So, numerator = x - 2
- According to the given condition: when 1 is subtracted from numerator and denominator both, the resulting new rational number in its simplest form is
