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tamaranim1 [39]
3 years ago
11

Given that f(x) =19x2 +152 solve the equation f(x) =0

Mathematics
1 answer:
m_a_m_a [10]3 years ago
6 0

Answer:

152

Step-by-step explanation:

f(x) =19x2 +152

f(0) = 190(0)^2 + 152

     = 152

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Reptile [31]

Answer:

106°

Step-by-step explanation:

Supplementary angles add up to 180°

180°- 74°

= 106°

6 0
3 years ago
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Can someone please help me with this
hammer [34]
It is 146 because it is equal to the other large angle.
3 0
3 years ago
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Which of the following is the equation of a hyperbola with center at (0, 0), with a = 4, b = 1, opening horizontally?
matrenka [14]

Answer:

The equation of the hyperbola is x²/16 - y²/1 = 1

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (0 , 0) and transverse axis parallel to the x-axis is

  x²/a² - y²/b² = 1

# The length of the transverse axis is 2a

# The coordinates of the vertices are (±a , 0)

# The length of the conjugate axis is 2b

# The coordinates of the co-vertices are (0 , ±b)

# The coordinates of the foci are (± c , 0),  

# The distance between the foci is 2c where c² = a² + b²

* Now lets solve the problem

∵ The center of the hyperbola is (0 , 0)

∵ It is opening horizontally

∴ x²/a² - y²/b² = 1

∵ a = 4 , b = 1

∴ a² = (4)² = 16

∴ b² = (1)² = 1

∴ x²/16 - y²/1 = 1

∴ The equation of the hyperbola is x²/16 - y²/1 = 1

6 0
3 years ago
How many solutions does the following equation have?<br> 35+ 4) = 3y + 123
kotegsom [21]

Answer:

y= -28

Step-by-step explanation:

35+4=3y+123

39=3y+123

-3y+39=123

-3y=123-39

-3y=84

y= -28

4 0
3 years ago
Use the definition of continuity and the properties of limits to show that the function
Zepler [3.9K]

Answer:

Applied the definition and the limit.

They had the same result, so the function is continuous.

Step-by-step explanation:

At function f(x) is continuous at x = a if:

\lim_{x \to a} f(x) = f(a)

In this question:

f(x) = x^{2} + 5(x-2)^{7}

At x = 3.

\lim_{x \to 3} x^{2} + 5(x-2)^{7} = 3^{2} + 5(3-2)^{7} = 14

f(3) = 3^{2} + 5(3-2)^{7} = 14

Since \lim_{x \to 3} f(x) = f(3), f(x) is continuous at x = 3.

7 0
3 years ago
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