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Lina20 [59]
2 years ago
8

What is the 30°-60°-right triangle theorem?

Mathematics
1 answer:
kondaur [170]2 years ago
4 0
<span>the 30°-60°-right triangle theorem states that the 
</span>In a right triangle, the hypotenuse is twice as long as a leg if and only if the measure of the
<span>angle opposite that leg is 30°
so the option C is correct from above all
</span>see the figure
hope it helps

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A single card is drawn from a 52 standard deck. Find the conditional probability that the card is a heart given that it's a jack
MakcuM [25]
You can use the formula for conditional probability as Puzzling did. However in this problem it is easier just to restrict yourself and enumerate the cases that are left. 

<span>There are 4 jacks. One of them is a heart. So the probability is 1/4. </span>

<span>If you want to look at what the formula for conditional probability does, it adjusts your probability by restricting the "universe". </span>

<span>P(heart and jack)/P(jack) </span>
<span>= (1/52)/(4/52) = 1/4</span>
7 0
3 years ago
Please tell me what is the answer for this question.
Dvinal [7]

Answer: The answer is A

4 0
3 years ago
Read 2 more answers
CAN SOMEONE PLEASE HELP ME I NEED THIS ASAP
Fittoniya [83]
The answer is y=-2/2+3
8 0
2 years ago
Twice x, plus 4, is the same as -6.
BARSIC [14]
Start by writing what is said:
2x + 4 = -6
From there just solve for x:

Subtract 4 from both sides
2x + 4 - 4 = -6 - 4
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Divide by 2 to get x by itself
2x/2 = -10/2
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6 0
3 years ago
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Suppose a tub has the shape of an elliptical paraboloid given by z = ax2+by2 (where a, b are some positive constants). If a marb
Umnica [9.8K]

Answer:

It would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

Step-by-step explanation:

It would roll to the direction of maximum decrease, which is the -1 times the direction of maximum increase, which is given by the gradient of the function.  

Since  

z =  ax^2  + by^2

For this case, the gradient of your function would be

\nabla z  = (2ax , 2by)

And  -1  times the gradient of your function would be

-\nabla z  = (-2ax , -2by)\\

Then, at

 (1,1,a+b),\\x = 1 \\y = 1

So it would go towards

v = (-2a,-2b)

The magnitud of that vector is

|v| =  2\sqrt{a^2+b^2}

and to conclude it would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

6 0
3 years ago
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