Area=πr^2 * β/360
=3.142*(6^2)(60/360)
18.852cm^2
option D is the answer
To solve this problem, let's set up a proportion, letting x represent the unknown number of gallons the faucet loses in 48 hours.
5 gallons / 20 hours = x gallons / 48 hours
To solve this proportion, we are going to use cross-products. This is the products of numerator of one fraction and the denominator of the other fraction set equal to one another. It results in the equation:
5 * 48 = 20 * x
Next we simplify by performing the operations.
240 = 20x
Finally, we divide both sides by 20 to get x alone on the right side of the equation.
12=x
Therefore, 12 gallons of water will be lost in 48 hours.
F(3) = t4(3) = 2
The value of the function at the point of expansion is the first (constant) term of the Taylor series.
Step-by-step explanation:
i) x (x+2)(3x)
ii) 3x^3+6x^2
iii) (x^2+2x) +(3x^2+6x) +(3x^2)
iv)7x^2+8x
