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Julli [10]
2 years ago
5

Solve this problem in your notebook using all four steps. Harvey is 3 times as old as Jane. The sum of their ages is 48 years. F

ind the age of each. Jane is a0 years old. Harvey is a1 years old.
Mathematics
1 answer:
JulsSmile [24]2 years ago
3 0
Harvey is 3 times as old as Jane." 
<span>h = 3j </span>

<span>"The sum of their ages is 48 years." </span>
<span>h + j = 48 </span>

<span>substitution </span>
<span>(3j) + j = 48 </span>
<span>4j = 48 </span>
<span>j = 12 </span>
<span>h = 3j = 36</span>
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\displaystyle\sum_{x\in\{0,2,a,b\}}\mathbb P(X=x)=1
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0\mathbb P(X=0)+2\mathbb P(X=2)+a\mathbb P(X=a)+b\mathbb P(X=b)=2.8
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7 0
3 years ago
A bird releases waste from a height of
shepuryov [24]

Answer:

5secs

Step-by-step explanation:

Given the equation of the height expressed ad;

h(t) = - 16t^2 + initial height

Given that initial height = 400feet

h(t) = - 16t^2 + 400

The waste will hit the ground at when h(t) = 0

substitute

0 =  - 16t^2 + 400

16t^2 = 400

t² = 400/16

t² = 25

t = √25

t = 5secs

Hence it will take the easte 5secs to hit the ground

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2 years ago
Which shows the correct first step to solving the system of equations in the most efficient manner? 3 x + 2 y = 17. x + 4 y = 19
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Answer:

a.)x = negative 4 y + 19

Step-by-step explanation:

i got it right on e2020 lol

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Suppose that a manager is interested in estimating the average amount of money customers spend in her store. After sampling 36 t
musickatia [10]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Step-by-step explanation:

Assuming this complete question: Which statement gives a valid interpretation of the interval?

The store manager is 90% confident that the average amount spent by the 36 sampled customers is between S38.01 and $44.29.

There is a 90% chance that the mean amount spent by all customers is between S38.01 and $44.29.

There is a 90% chance that a randomly selected customer will spend between S38.01 and $44.29.

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

8 0
3 years ago
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