Givens
y = 2
x = 1
z(the hypotenuse) = √(2^2 + 1^2) = √5
Cos(u) = x value / hypotenuse = 1/√5
Sin(u) = y value / hypotenuse = 2/√5
Solve for sin2u
Sin(2u) = 2*sin(u)*cos(u)
Sin(2u) = 2(
) = 4/5
Solve for cos(2u)
cos(2u) = - sqrt(1 - sin^2(2u))
Cos(2u) = - sqrt(1 - (4/5)^2 )
Cos(2u) = -sqrt(1 - 16/25)
cos(2u) = -sqrt(9/25)
cos(2u) = -3/5
Solve for Tan(2u)
tan(2u) = sin(2u) / cos(2u) = 4/5// - 3/5 = - 0.8/0.6 = - 1.3333 = - 4/3
Notes
One: Notice that you would normally rationalize the denominator, but you don't have to in this case. The formulas are such that they perform the rationalizations themselves.
Two: Notice the sign on the cos(2u). The sin is plus even though the angle (2u) is in the second quadrant. The cos is different. It is about 126 degrees which would make it a negative root (9/25)
Three: If you are uncomfortable with the tan, you could do fractions.

Answer:
y = 3x - 10
y = 2x - 7
&
y = 5x - 16
y = x - 4
Step-by-step explanation:
Coordinates of point A are (3, - 1)
It satisfies the following system of linear equations:
y = 3x - 10
y = 2x - 7
&
y = 5x - 16
y = x - 4
Answer: the weight of each bags are 1.85kg, 1.85kg and 3.05 kg
Step-by-step explanation:
Total weight of the three bags is
6 3/4 kg. Converting to decimal, it becomes 6.75 kg.
Two of them have the same weight. Let x represent the bags of equal weight. Their total weight would be 2x. The third bag is heavier than each of the bags of equal weight by 1 1/5 kg. Converting to decimal, it becomes 1.2kg. It means that the weight of the third bag would be
x + 1.2
Therefore, for the three bags,
2x + x + 1.2 = 6.75
3x = 6.75 - 1.2 = 5.55
x = 5.55/3 = 1.85
Weight of the third bag is
1.85 + 1.2 = 3.05kg
5a^2b^2+8. That would be ur answer