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madam [21]
3 years ago
10

I really need help ASAP

Mathematics
1 answer:
kolezko [41]3 years ago
6 0

Answer:

The first 2 on top is not a function. The 3rd one on top and the bottom 2 are functions.

Step-by-step explanation:

The x-value cannot have more than 1 y-value or else when you plot the points on the graph, it doesn't meet the vertical line test. The vertical line test indicates whether or not the graph is a function. Different x-values can have the same y-value.

Function examples: (3,-4), (5,0), (0,-4), (1,2)

Not a Function examples: (0,8), (2,-1), (0,-2), (-5,3)

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Solve the system. find x,y, and z please show all steps<br><br> x-y+z=1<br> x+y+3z=-3<br> 2x-y+2z=0
Mariulka [41]

Solving the system we get, x= -1, y= -2 and z= 0

Step-by-step explanation:

Solving the equations to find x, y and z

x-y+z=1\,\,\,eq(1)\\x+y+3z=-3\,\,\,eq(2)\\2x-y+2z=0\,\,\,eq(3)

Adding eq(1) and eq(2)

x-y+z=1\\x+y+3z=-3\\--------\\2x+4z=-2\,\,\,\,eq(4)\\

Adding eq(2) and eq(3)

x+y+3z=-3\\2x-y+2z=0\\----------\\3x+5z=-3\,\,\,eq(5)

Multiplying eq(4) by 3 and eq(5) by 2

6x+12z=-6\\6x+10z=-6\\-\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\\----------\\2z=0\\z=0

So, value of z =0

Putting value of z in eq(4)

2x+4z=-2\\2x+4(0)=-2\\2x=-2\\x=-1

So, value of x = -1

Now putting value of z=0 and x =-1 in equation 1

x-y+z=1\\-1-y+0=1\\-y=1+1\\-y=2\\y=-2

So, value of y = -2

So, solving the system we get, x= -1, y= -2 and z= 0

Keywords: Solve the system

Learn more about Solve the system at:

  • brainly.com/question/6075514
  • brainly.com/question/2386054
  • brainly.com/question/7361044

#learnwithBrainly

7 0
3 years ago
What is the 52nd term of the sequence below?
VladimirAG [237]
Because the difference between any term and the previous term is a constant, this is an arithmetic sequence because of that constant which is referred to as the common difference, d.  Which in this case is -35--38=-32--35=3

Any arithmetic sequence can be expressed as:

a(n)=a+d(n-1), a=initial term, d=common difference, n=term number.

In this case a=-38 and d=3 so

a(n)=-38+3(n-1)  which we can simplify to

a(n)=-38+3n-3

a(n)=3n-41, so the 52nd term is:

a(52)=3(52)-41

a(52)=156-41

a(52)=115
3 0
3 years ago
..Urgent.. 600 students attend Ridgewood Junior High School. 10% of students bring their lunch to school everyday. How many stud
zysi [14]

Answer:

Number of student bring their lunch = 60

Step-by-step explanation:

Given:

Total number of student = 600

Student bring their lunch = 10%

Find:

Number of student bring their lunch

Computation:

Number of student bring their lunch = Total number of student x Student bring their lunch

Number of student bring their lunch = 600 x 10%

Number of student bring their lunch = 60

3 0
3 years ago
The segments shown below could form a triangle.
-BARSIC- [3]

Answer:

True. It could. Sorry my answer just has to be 20 characters long

7 0
2 years ago
I don't get it and I have tried it multiple ways
jasenka [17]

9514 1404 393

Answer:

  9350 m²

Step-by-step explanation:

There are several ways you can go at this. Here are 3 of them:

  1. along an extension of the lower right vertical edge, divide the figure into a rectangle and a right triangle.
  2. between the upper left corner and the inside corner at lower right draw a diagonal line to divide the figure into a trapezoid and a triangle.
  3. subtract the area of the trapezoid at the right from the area of the bounding rectangle

__

The relevant formulas for area are ...

  rectangle: A = LW . . . . . . . . . . . length times width

  trapezoid: A = (1/2)(b1 +b2)h . . . b1, b2 are the bases, h is the height

  triangle: A = (1/2)bh . . . . . . . . . . . b is the base, h is the height

__

Here's what those computations look like:

1. rectangle: 60m wide by 80 m high = 4800 m².

  right triangle: base 190-60 = 130 m; height = 80-10 = 70 m.

     area = (1/2)(130 m)(70 m) = 4550 m²

  figure area = 4800 m² +4550 m² = 9350 m² . . . . area of figure

__

2. The trapezoid has bases of 80 m and 10 m, and a height of 60 m. Its area is ...

  A = (1/2)(80 m +10 m)(60 m) = 2700 m²

The triangle has a base of 190 m and a height of 80-10 = 70 m. Its area is ...

  A = (1/2)(190 m)(70 m) = 6650 m²

Then the total area is 2700 m² +6650 m² = 9350 m² . . . total area

__

3. The bounding rectangle is 190 m by 80 m, so its area is ...

  A = LW = (190 m)(80 m) = 15200 m²

The (negative) trapezoid at right has bases of 10 m and 80 m, and a width of 190-60 = 130 m. Its area is ...

  A = (1/2)(10 m +80 m)(130 m) = 5850 m²

The area of the figure is the difference between these:

  figure area = 15200 m² -5850 m² = 9350 m² . . . figure area

7 0
3 years ago
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