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Ira Lisetskai [31]
3 years ago
12

A 25.0-N force is applied to a 5.0-kg object to accelerate is rightwards. The object encounters 15.0-N of friction. Determine th

e acceleration of the object. (Neglect air resistance.) show your work below.
Physics
1 answer:
djyliett [7]3 years ago
6 0

Answer: The acelaration is 2 m/s^2

Explanation: Using the second Newton law

The total force acting over the object is equal to the mass x accelaration, that is:

We considerer the applied force to the object equal to 25N

and the friction force of 15 N

25N-15N= m*a

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Lera25 [3.4K]

Answer:

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Explanation:

From the question we are told that

     The albedo value of Mars is  A_1  = 0.15

      The albedo value of Mars is  A_2  = 0.15

       The surface temperature of Mars is  T_1 = 220 K

        The surface temperature of Venus is  T_2 = 700 K

          The distance of Mars from the sun is d_m = 2.28*10^8 \ km = 2.28*10^8* 1000 = 2.28*10^{11} \  m

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The solar constant for Mars is mathematically represented as

 

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Where \sigma is the Stefan's constant with a value  \sigma = 5.6*10^{-8} \ Wm^{-2} K^{-4}

So substituting values

         T = \frac{6.28 *10^{7} * (7*10^8)^2 * (1-0.15)}{(5.67 *10^{-8}) * (2.28 *10^{11})^2)}

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So the greenhouse effect on Mars is  

           G_m =  T -  T_1

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For this piece of wire . . .

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<em>Resistance = (10 and 1/6) ohms</em>

Since you know the voltage and current, the length doesn't matter.

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