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Amanda [17]
3 years ago
8

A 1.5m wire carries a 6 A current when a potential difference of 61 V is applied. What is the resistance of the wire?

Physics
1 answer:
Alisiya [41]3 years ago
7 0

Resistance = (voltage) / (current)

For this piece of wire . . .

Resistance = (61 volts) / (6 Amperes)

Resistance = (61/6) (V/A)

<em>Resistance = (10 and 1/6) ohms</em>

Since you know the voltage and current, the length doesn't matter.

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A coil has an inductance of 6.00 mH, and the current in it changes from 0.200 A to 1.50 A in a time interval of 0.300 s. Find th
Andre45 [30]

Answer:

0.026 V

Explanation:

Given that,

Inductance of the coil, L = 6 mH

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We need to find the magnitude of the average induced emf in the coil during this time interval. The formula for the induced emf is given by :

\epsilon=L\dfrac{dI}{dt}\\\\=6\times 10^{-3}\times \dfrac{1.5-0.2}{0.3}\\\\=0.026\ V

So, the magnitude of induced emf is 0.026 volts.

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3 years ago
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Answer:

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Kepler's 3rd Law also known as the Harmonic Law states that;

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An engine extracts 452.8kJ of heat from the burning of fuel each cycle, but rejects 266.7 kJ of heat (exhaust, friction,etc) dur
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