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ziro4ka [17]
3 years ago
9

A singly charged 7Li ion has a mass of 1.16 10-26 kg. It is accelerated through a potential difference of 523 V and subsequently

enters a uniform magnetic field of magnitude 0.370 T perpendicular to the ion's velocity. Find the radius of its path.
Physics
1 answer:
mel-nik [20]3 years ago
8 0

Answer:

R=0.023m

Explanation:

From the question we are told that:

Mass m=1.16*10^{-26}

Potential difference V=523V

Magnitude m=0.370 T

Generally the equation for Velocity is mathematically given by

\frac{1}{2}mv^2=ev

v=\frac{2ev}{m}

v=\frac{2*1.6*10^{-19}*542}{1.16*10^{-26}}

v=12.22*10^4m/s

Generally the equation for Force is mathematically given by

F=qvBsin \theta

Where

qVB=m\frac{v^2}{R}

F=m\frac{v^2}{R}sin\theta

Therefore

R=\frac{mv}{qB sin \theta}

R=\frac{1.6*10^{-26}*12.2*10^{4}}{1.60*10^{-19}*0.394 sin 90}

R=0.023m

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