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Ilia_Sergeevich [38]
3 years ago
14

If i purchase a product for $79.99 and two accessories for 9.99 and 7.00 how much will i owe after taxes applies 8.75%

Mathematics
1 answer:
ehidna [41]3 years ago
8 0

Answer:

The price will be $105.47

Step-by-step explanation:

Given that i purchase a product for $79.99 and two accessories for $9.99 and $7.00. we have to find how much will i owe after taxes applies 8.75%

Now, the cost price of the product and the two accessories will be

$79.99+$9.99+$7.00

= $96.98

Now, also the tax applies at the rate 8.75%

∴ Tax=8.75\%\thinspace of\thinspace96.98

               =8.48575=8.49(approx)

Hence, the price which i owe after taxes will be $96.98+$8.49=$105.47

                     

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Hiroshi has 4 engines and 18 box cars. Find the ratio of engines to box cars. Write the ratio as a fraction in simplest form.
lyudmila [28]
To write a ratio as a fraction, we simply take the first number in the ratio and make it the numerator while taking the second number in the ratio and making it the denominator.

Because we want the ratio of engines to box cars, our ratio should be:

number of engines/number of box cars

When we substitute in our respective values, we get:

4/18

To simplify this ratio, we have to find the GCF, or greatest common factor of the numerator and the denominator, which in this case is 2. To simplify, we divide both the numerator and the denominator by the GCF, as follows:

4/2 / 18/2

When we simplify, we get:

2/9

Therefore, your answer is 2/9.

Hope this helps!
4 0
3 years ago
The force needed to stop a car varies directly as its weight W and the square root of velocity V are inversely as the distance d
svet-max [94.6K]

Answer:

Step-by-step explanation:

8 0
3 years ago
Evaluate n+2x2 when n=3 and x=−2.
krok68 [10]

Answer:

When n=3 and x=−2  the answer is 11.

Step-by-step explanation:

Given:

Let p (n,x) be the function such that

p (n,x) = n + 2x^{2}

To Find:

p (n,x) = p ( 3, -2) = ?

Solution:

p (n,x) = n + 2x^{2}

Substituting n = 3 and x = -2 we get

p (3, -2) = 3 + 2(-2)^{2}

Negative square gives positive number therefore (-2)²=4

p (3, -2) = 3 + 2\times 4

p (3, -2) = 3 + 8\\p (3, -2) = 11

When n=3 and x=−2  the answer is 11.

7 0
3 years ago
2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One
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y'=(t+y)^2-1

Substitute u=t+y, so that u'=y', and

u'=u^2-1

which is separable as

\dfrac{u'}{u^2-1}=1

Integrate both sides with respect to t. For the integral on the left, first split into partial fractions:

\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1

\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt

\dfrac12(\ln|u-1|-\ln|u+1|)=t+C

Solve for u:

\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C

\ln\left|1-\dfrac2{u+1}\right|=2t+C

1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}

\dfrac2{u+1}=1-Ce^{2t}

\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}

u=\dfrac2{1-Ce^{2t}}-1

Replace u and solve for y:

t+y=\dfrac2{1-Ce^{2t}}-1

y=\dfrac2{1-Ce^{2t}}-1-t

Now use the given initial condition to solve for C:

y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}

so that the particular solution is

y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}

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