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STatiana [176]
3 years ago
12

Which of the following is the reason why an engineer creates a model of something he or she

Physics
1 answer:
MatroZZZ [7]3 years ago
4 0

Answer:

so then the main bild and or project dont get ruined and to make sure everything will fit and work right

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What are the uses of nuclear power ? ​
Alona [7]

Answer:

the main reason is electricity

Explanation:

there are many different things nuclear power does that are good and bad.

5 0
4 years ago
The fumes of lighted 'incense stick' spread in the whole room due to-​
Firlakuza [10]

Answer: burning of the incense and air drift in the room

Explanation:  the smoke will automatically rise to the top of the room and then with air drift if would help spread further around the room and spread the smell

7 0
3 years ago
Given vectors D (3.00 m, 315 degrees wrt x-axis) and E (4.50 m, 53.0 degrees wrt x-axis), find the resultant R= D + E. (a) Write
fomenos

Answer:

(a) \vec{R}= 4.83\ m\ \hat{i}+1.47\ m\ \hat{j}

(b) (5.05 m, 16.93 degrees wrt x-axis)

Explanation:

Given:

  • \vec{D} = (3.00 m, 315 degrees wrt x-axis)
  • \vec{E} = (4.50 m, 53.0 degrees wrt x-axis)

Let us first fond out vector D and E in their rectangular form.

\vec{D} = (3\cos 315^\circ\ \hat{i}+3\sin 315^\circ\ \hat{j})\ m\\\Rightarrow \vec{D} = (2.12\ \hat{i}-2.12\ \hat{j})\ m\\

Similarly,

\vec{E} = (4.5\cos 53^\circ\ \hat{i}+4.5\sin 53^\circ\ \hat{j})\ m\\\Rightarrow \vec{D} = (2.71\ \hat{i}+3.59\ \hat{j})\ m\\\because \vec{R}=\vec{D}+\vec{E}\\\therefore \vec{R} = (2.12\ \hat{i}-2.12\ \hat{j})\ m+(2.71\ \hat{i}+3.59\ \hat{j})\ m\\\Rightarrow \vec{R} = (4.83\ \hat{i}+1.47\ \hat{j})\ m

Part (a):

We can write the resultant vector R as below:

\vec{R} = (4.83\ \hat{i}+1.47\ \hat{j})\ m

Part (b):

Magnitude\ of\ resultant = \sqrt{4.83^2+1.47^2}\ m = 5.05\ m\\\textrm{Direction in angle with the x-axis} = \theta = \tan^{-1}(\dfrac{1.47}{4.83})= 16.93^\circ

Since both the components of the resultant lie on the positive x and y axes. So, the resultant makes an acute angle with the positive x-axis.

So, R = (5.05 m, 16.93 degrees wrt x-axis)

3 0
3 years ago
A 43-kg child sits in a massless swing. With what horizontal force must the seat be pulled so that the ropes form an angle of 35
GenaCL600 [577]

Answer:

F_x = 295.4N

Explanation:

180°-90°-35°= 55°

F= m(a)

F_y = 43kg(9.81m/s²)

F_y = 421.83N

tan(55°) = 421.83N/F_x

F_x = 421.83N/tan(55°)

F_x = 295.3685458N

7 0
3 years ago
Ben Walks 2 m from his desk to the teachers Desk. From the teachers Desk, he then walks 3 m in the same direction to the classro
Juliette [100K]
None of the tables that you have attached is a correct one.
7 0
3 years ago
Read 2 more answers
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