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3 years ago

Which example best demonstrates how unbalanced forces change the speed of an object's motion?

1 answer:

4 0

I don’t see a picture but unbalanced forces could be two boys pushing with a combined force of 400 Newton’s but the surface of what the box is laying on being 600 meaning since the ground is creating a higher force in the form of friction it will slow the boys down. When forces are unbalanced it means that the object can not be still or moving at a constant speed when one force is greater by a significant amount the object either slows quickly or accelerates fast depending on which factor is greater.

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A spring has a spring constant of 200 N/m. How much elastic potential energy is stored in the spring when it is stretched by 0.1

adoni [48]

Answer:

D, 1J

Explanation:

PE=1/2kx^2 and plug in the variables.

PE=1/2 x 200 x 0.1^2= 1J

7 0

3 years ago

An object moves in uniform circular motion at 50 m/s and takes 1.0 second to go a quarter circle. What is the radius of the circ

dimulka [17.4K]

The would answer be .50 m

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4 years ago

A tennis ball is hit with a vertical speed of 10 m/s and a horizontal speed of 30 m/s. How far will the ball travel horizontally

sweet-ann [11.9K]

Answer:

D) 60 m

Explanation:

We can use the constant acceleration equation that contains displacement, initial velocity, acceleration, and time. We want to solve for the time that the ball was in the air first.

Δx = v_i * t + 1/2at²

Let's use this equation in terms of the y-direction.

Δx_y = (v_i)y * t + 1/2a_y * t²

The vertical displacement will be 0 meters since the ball will be on the floor. The initial vertical velocity is 10 m/s, the vertical acceleration is g = 10 m/s², and we are going to solve for time t.

Let's set the upwards direction to be positive and the downwards direction to be negative. We must use -g to be consistent with our other values.

Plug the known values into the equation.

0 m = 10 m/s * t + 1/2(-10 m/s²) * t²

Simplify the equation.

0 = -10t + 5t²
0 = 5t² - 10t

Factor the equation.

0 = 5t(t - 2)

Solve for t by setting both factors to 0.

5t = 0
t - 2 = 0

We get t = 0, t = 2. We must use t = 2 seconds because it is the only value for t that makes sense in the problem.

Now that we have the time that the ball was in the air, we can use the same constant acceleration equation to determine the horizontal displacement of the tennis ball. We will use this equation in terms of the x-direction:

Δx = v_i * t + 1/2at²
Δx_x = (v_i)x * t + 1/2a_x * t²

Plug the known values into the equation.

Δx_x = 30 m/s * 2 sec + 1/2(0 m/s²) * (2 sec)²

We can eliminate the right side of the equation since anything multiplied by 0 outputs 0.

Δx_x = 30 * 2
Δx_x = 60

The horizontal displacement of the ball is 60 meters. Therefore, the answer is D) 60 m.

4 0

3 years ago

If Ms. Ramirez drops a watermelon from the top of the second-floor fire escape outside her room, and it takes 1.5 seconds to hit

mamaluj [8]

The velocity of the watermelon as it hits the ground is 14.715 m/s.

Given the data in the question;

Since the Watermelon was dropped from rest,

Initial velocity of the Watermelon; $u = 0m/s$

Time taken for the Watermelon to hit the ground; $t = 1.5s$

We know that, Acceleration due to gravity; $g = 9.81 m/s^2$

Now, we determine the velocity of the watermelon as it hits the ground which is the final velocity.

From the First Equation of Motion:

$v = u + at$

Now, under gravity, acceleration ''a" will Acceleration due to gravity; $g = 9.81m/s^2$ , "v" is the final velocity, "u" is the initial velocity and "t" is the time taken.

So, we substitute our values into the equation

$v = 0m/s\ +\ ( 9.81m/s^2\ * 1.5s )\\\\v = ( 9.81m/s^2\ * 1.5s )\\\\v = 14.715 m/s$

Therefore, the velocity of the watermelon as it hits the ground is 14.715 m/s

Learn more; brainly.com/question/13275688

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3 years ago

Why does the earth stay in orbit around the sun instead of drifting away from it into space?

pychu [463]

Answer:

b it is b part answer i think so

3 0

2 years ago