Answer:
x ≥6
Step-by-step explanation:
Given the product:
√(x-6)*√(x+3)
The function has to be defined if x ≥0
Hence;
√(x-6)*√(x+3)≥0
Find the product
√(x-6)(x+3)≥0
Square both sides
(x-6)(x+3)≥0
x-6≥0 and x+3≥0
x≥0+6 and x ≥0 - 3
x ≥6 and x ≥-3
Hence the required inequality is x ≥6
Answer:
x = -32
Step-by-step explanation:
You must get the variable (x) on one side in order to solve this problem. Do this by multiplying 4 on both sides in order to get rid of the fraction. -8 times 4 is -32, so the equation should now read to be x=-32
(2x2 + x − 3 )(x − 1.)
= 4x3 + x2 - 3x - 2x2 - x + 3
= 4x3 - x2 - 4x + 3
option 4
The diagram shows statements to prove that both triangles are congruent.
Hence;
Step 1 showed two sides that are congruent for both triangles
Step 2 showed two angles that are congruent
Step 3 showed two sides that are congruent
Therefore, the triangles are congruent by the side-angle-side theorem