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Talja [164]
3 years ago
11

Indicate whether each of the following fractions is proper or improper. a. 4⁄16 b. 75⁄70 c. 2⁄15 d. 6⁄6

Mathematics
2 answers:
Gemiola [76]3 years ago
8 0
An proper fraction is a fraction where the denominator is larger than the numerator.
An improper fraction is a fraction where the numerator is larger than or equal to the denominator.

a. 4/16
The denominator is 16. The numerator is 4. The denominator is larger than the numerator; thus, this is a proper fraction.

b. 75/70
The denominator is 70. The numerator is 75. The numerator is larger than the denominator; thus, this is an improper fraction.

c. 2/15
The denominator is 15. The numerator is 2. The denominator is larger than the numerator; thus, this is a proper fraction.

d. 6/6
The denominator is 6. The numerator is 6. The numerator is equal to the denominator; thus, this is an improper fraction.
Westkost [7]3 years ago
7 0
75/70 is an Improper Fraction
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Answer:

Hello your question is incomplete attached below is the complete question

answer : 192.15 pounds

Step-by-step explanation:

Given :

weight =  - 99.41 + 3.94*Height

R^2 = 0.81

SER = 10.2

<em><u>Determine the regression weight prediction</u></em>

Height of man = 74 inches

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therefore the regression weight prediction = 192.15 pounds

4 0
3 years ago
What is square root of 81
Doss [256]
The square root of 81 is 9, this can be proven by squaring 9, which's result is 81.
4 0
3 years ago
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What is the total area of the regions between the curves y = 6x2 − 18x and y = −6x from x = 1 to x=3?.
kvasek [131]

Using integration, it is found that the area between the two curves is of 22 square units.

<h3>What is the area between two curves?</h3>

The area between two curves y = f(x) and y = g(x), in the interval from x = a to x = b, is given by:

A = \int_{x = a}^{x = b} |f(x) - g(x)| dx

In this problem, we have that:

f(x) = 6x^2 - 18x, g(x) = -6x, a = 1, b = 3.

Hence, the area is:

A = \int_{1}^3 |6x^2 - 12x| dx

A = |x^3 - 6x^2|_{x = 1}^{x = 3}

Applying the Fundamental Theorem of Calculus:

A = |3^3 - 54 - 1^3 + 6|

A = 22

The area between the two curves is of 22 square units.

More can be learned about the use of integration to find the area between the two curves at brainly.com/question/20733870

8 0
3 years ago
Find all solutions to the equation in the interval [0, 2π).
ANEK [815]

Answer:

x = π/6, π/2, 5π/6, 3π/2

Step-by-step explanation:

cos x = sin(2x)

Use double angle formula.

cos x = 2 sin x cos x

Move everything to one side and factor.

cos x − 2 sin x cos x = 0

cos x (1 − 2 sin x) = 0

Set each factor to 0 and solve.

cos x = 0

x = π/2, 3π/2

1 − 2 sin x = 0

sin x = 1/2

x = π/6, 5π/6

The total solution is:

x = π/6, π/2, 5π/6, 3π/2

6 0
4 years ago
Can you change this into y=x format so I can graph it easier please, thankyou. I'll give you brainliest.
Natali [406]
Y=-3x+1 this is the answer I think
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