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3 years ago

7

Write 720,080 in expanded form with exponents

1 answer:

yuradex [85]3 years ago

4 0

MrBillDoesMath!

Answer:

720,080 = 700,000 + 20,000 + 80 =

7 * 100000 + 2 * 10000 + 0 * 1000 + 0*100 + 8*10 + 0*1 =

7 * 10^5 + 2 * 10^4 + 0 * 10^3 + 0* 10^2 + 8 * 10

MrB

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Can somebody plz help me with these two and explan why the answers are correct

aliina [53]

Answer:

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Step-by-step explanation:

6 0

3 years ago

PLZ HURRY!!!!!!!!!!!!!<br> Simplify. <br> −4x^2(5x^4−3x^2+x−2)

Simora [160]

$\bold{Answer}$

$\boxed{\bold{-20x^6+12x^4-4x^3+8x^2}}$

$\bold{Explanation}$

$\bold{Simplify: \ -4x^2\left(5x^4-3x^2+x-2\right)}$

$\bold{------------------}$

$\bold{Distribute \ Parenthesis}$

$\bold{\left(-4x^2\right)\cdot \:5x^4+\left(-4x^2\right)\left(-3x^2\right)+\left(-4x^2\right)x+\left(-4x^2\right)\left(-2\right)}$

$\bold{Apply \ Addition \ / \ Subtraction \ Rules: \ +\left(-a\right)=-a,\:\:\left(-a\right)\left(-b\right)=ab}$

$\bold{-4\cdot \:5x^4x^2+4\cdot \:3x^2x^2-4x^2x+4\cdot \:2x^2}$

$\bold{Simplify \ -4\cdot \:5x^4x^2+4\cdot \:3x^2x^2-4x^2x+4\cdot \:2x^2: \ -20x^6+12x^4-4x^3+8x^2}$

$\bold{-20x^6+12x^4-4x^3+8x^2}$

$\boxed{\bold{Eclipsed}}$

5 0

3 years ago

Dada la ecuacion 25x2 + 4y2 = 100, determina las coordenadas de los vertices, focos, las longitudes de los respectivos ejes mayo

Likurg_2 [28]

Answer:

The given equation is

$25x^{2} +4y^{2}=100$

Which represents an elipse.

To find its elements, we need to divide the equation by 100

$\frac{25x^{2} +4y^{2} }{100} =\frac{100}{100} \\\frac{x^{2} }{4} +\frac{y^{2} }{25} =1$

Where $a^{2} =25$ and $b^{2}=4$ . Remember that the greatest denominator is $a$ , and the least is $b$ . So, we extract the square root on each equation.

$a=5$ and $b=2$ .

In a elipse, we have a major axis and a minor axis. In this case, the major axis is vertical and the minor axis is horizontal, that means this is a vertical elipse.

The length of the major axis is $2a=2(5)=10$ .

The length of the minor axis is $2b=2(2)=4$ .

The vertices are $(0,5);(0,-5)$ and $(2,0);(-2,0)$ .

Now, the main parameters of an elipse are related by

$a^{2}=b^{2} +c^{2}$ , which we are gonna use to find $c$ , the parameter of the focus.

$c=\sqrt{a^{2}-b^{2} }=\sqrt{25-4}=\sqrt{21}$

So, the coordinates of each focus are $(0,\sqrt{21})$ and $(0,-\sqrt{21})$

The eccentricity of a elipse is defined

$e=\frac{c}{a}=\frac{\sqrt{21} }{5} \approx 0.92$

The latus rectum is defined

$L=\frac{2b^{2} }{a}=\frac{2(4)}{5} =\frac{8}{5} \approx 1.6$

Finally, the graph of the elipse is attached.

7 0

3 years ago

Two show your work questions

Svet_ta [14]

Answer:

x = 1; y = 1; z = 0

Step-by-step explanation:

First problem:

First equation minus second equation: 3y + 2z = 3 Eq. A

Second equation plus third equation: 2y + 4z = 2 Eq. B

-2 times Eq. A plus Eq. B: -4y = -4

y = 1

Substitute y = 1 in Eq. A: 3 + 2z = 3

2z = 0

z = 0

Substitute z = 0 and y = 1 in original first equation:

-2x + 2 + 0 = 0

-2x = -2

x = 1

Answer: x = 1; y = 1; z = 0

5 0

3 years ago

What is the answer to sin48

gogolik [260]

Round it to 1lolollololo

4 0

3 years ago