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lubasha [3.4K]
3 years ago
11

Which equation describes the line whose x-intercept is (4,0) and whose y-intercept is (0,-3)?

Mathematics
1 answer:
lilavasa [31]3 years ago
7 0

Answer:

y =  \frac{3}{4}x - 3

Step-by-step explanation:

In slope intercept form y = mx + b

We have the y intercept already so our equation becomes y = mx -3. Now we need to figure out the slope, we do this by subtracting the y values from both points and the x values from both points:

-3 - 0 = -3

0 - 4 = -4

Slope = -3/-4 the negatives cancel and now we have 3/4 as the slope.

Now the equation is y = 3/4x -3

y \:  =  \: \frac{3}{4} x \:   - 3

Double checking by inputting values such as x = 0 we now get (0, -3) which is correct and if the x-intercept is 4 then it should give us a y value of 0 which = (4,0). Yep! This is the correct linear equation for the line described

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