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3 years ago

Question 6 of 25

Mathematics

2 answers:

sladkih [1.3K]3 years ago

7 0

Answer:

Step-by-step explanation:

When you put a down payment on something that means you are buying/reserving for yourself. So when he's paying per month he will keep the ring until he misses a payment or keeps it until he pays it off

A P E X

Please Give brainliest

MA_775_DIABLO [31]3 years ago

5 0

Answer:

Step-by-step explanation:

a p e x

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Average rate of change

Ganezh [65]

Answer:

The average rate of change in that space would be 12.

Step-by-step explanation:

To find this, use the two ordered pairs (-1, 3) and (1, 27) in the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (27 - 3)/(1 - -1)

m = 24/2

m = 12

7 0

3 years ago

Three friends worked out on treadmills at the gym. Aiden walked 2 miles in 3/4 hour. Kira walked 1 3/4 mile in 30 minutes. Joe w

geniusboy [140]

Answer:

kira

Step-by-step explanation:

1.75*4 is greater than 1*5

3 0

3 years ago

A 2 quart container of window cleaner cost $6.96. What is the price per cup?

marissa [1.9K]

Answer:

$0.87

Step-by-step explanation:

2 quarts = 8 cups

$6.96 ÷ 8 = $0.87

4 0

3 years ago

Read 2 more answers

you plant 15 tulip bulbs and 10 of them grow into flowers to bloom. If you plant 21 more re tulips bulbs, predict how many of th

harina [27]

Answer:

14 more flower would bloom if 21 more tulip bulb is planted.

Step-by-step explanation:

Given ratio for tulip bulbs and flowers is 15:10.

Now, finding number of flower to bloom if 21 tulip bulb are planted.

Assume if 21 tulip bulbs are planted then number of flower would bloom be"x"

ratio given: $\frac{Tulip\ bulbs}{ Flower} = \frac{15}{10} = \frac{21}{x}$

Cross multiplying the ratio to get:

⇒x= $\frac{21\times 10}{15} = \frac{210}{15}$

∴ $x= 14\ flowers$

Hence, 14 flowers would bloom if 21 tulip bulb are planted.

If total tulip bulb is $15+21= 36$ , then $10+14= 24\ flowers$ would bloom.

5 0

3 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago