<span>Ans : a)
What is the standard deviation of this sampling distribution?
Ď /âšn
= 60/âš840
=2.0702
b)
1 standard deviation of the mean
= (1) 2.07
= 2.07
c)
272+/- 1(2.07)
(269.93, 274.07)</span>
Answer:
40% probability that the package was weighed by Employee C
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Incorrect package.
Event B: Weighed by Employee C.
A supermarket has three employees who equally packages and weighs produce.
This means that
Employee C records the correct weight 94% of the time
So incorrectly 6% of the time, which means that
Probability of an incorrect package:
4% of 1/3(A)
5% of 1/3(B)
6% of 1/3(C)
So
What is the probability that the package was weighed by Employee C?
40% probability that the package was weighed by Employee C