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Nastasia [14]
2 years ago
12

MARK BRAINILEST

Mathematics
2 answers:
dusya [7]2 years ago
6 0

Answer:

a greater-than negative 21 and one-third

Step-by-step explanation:

3/4a>-16

divide both sides by 3/4

a>-16*4/3

a>-64/3

a>-21 1/3

so then

a greater-than negative 21 and one-third

luda_lava [24]2 years ago
4 0

Answer: number 1 greater-than negative 21 and one-third

Step-by-step explanation:

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Evaluate the expression 4 1/2 ÷ 3/4
Darya [45]

Answer: 6

Step-by-step explanation:

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2 years ago
The whole number m is a term in an arithmetic sequence with common difference 2. Show that the sum of the term m and the next tw
Igoryamba

Answer:

S

ThenSn=n(a1+an)2Sn=n(a1 + an)2 , where nn is the number of terms, a1a1 is the first term and anan is the last term. The sum of the first nn terms of an arithmetic sequence is called an arithmetic series .

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3 0
3 years ago
Read 2 more answers
I need some help with this, I am supposed to solve for x
liq [111]

They are the same measurements, because:

from 10x + 5, first do vertical angle.

then, alternate interior angle,

then vertical angle again,

and another alternate interior angle.

For each vertical and alternate interior angles, the measurements stay the same.


Set them equal to each other, isolate and solve for x.

10x + 5 = 11x - 1

First, isolate the x. Subtract 10x from both sides, and add 1 to both sides

10x (-10x) + 5 (+1) = 11x (-10x) -1 (+1)

Simplify

5 + 1 = 11x - 10x

6 = x

x = 6

6 is your answer for x.

hope this helps

3 0
3 years ago
Points R, S, and T are collinear, and S is between R and T, in addition, RS = 2x-4, ST = 3x+2, and RT = 13. Find the value of RS
Alex17521 [72]

Answer:

RS = 2

Step-by-step explanation:

Points R, S, and T are collinear, and S is between R and T, in addition, RS = 2x-4, ST = 3x+2, and RT = 13. Find the value of RS

Hence:

RS + ST = RT

2x - 4 + 3x + 2 = 13

2x + 3x - 4 + 2 = 13

5x - 2 = 13

5x = 13 + 2

5x = 15

x = 15/5

x = 3

To find the value of RS

RS = 2x-4

RS = 2 × 3 - 4

RS = 6 - 4

RS = 2

5 0
2 years ago
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