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tatyana61 [14]
2 years ago
8

The question is in the pic :)

Mathematics
2 answers:
Scrat [10]2 years ago
8 0
I think it’s either a or d
Dovator [93]2 years ago
6 0

d

Step-by-step explanation:

trust me

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What is the value of the product (3-2i)(3+2i)?
Helga [31]

Answer:

13

Step-by-step explanation:

(3-2i)(3+2i) = 9  + 6i - 6i - 4i^2

9 - 4i^2

9 + 4 = 13

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128/8 in distributive property
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A concession stand sells two sizes of popcorn. The small bag holds 20 ounces and costs $4, and the large bag holds 32 ounces and
Usimov [2.4K]

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1/3 off the regular price of $51
jolli1 [7]

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34.00

Step-by-step explanation:

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2 years ago
Rebecca has 12 photos she wants to hang side by side on her wall.A. If she only wants to display 8 of the photos, in how many wa
Mariana [72]

A.

If she will choose 8 from 12 photos, the total number of ways she can choose is given by a combination of 12 choose 8, since the order of the photos doesn't matter.

The formula for a combination of n choose p is:

C(n,p)=\frac{n!}{p!(n-p)!}

For n = 12 and p = 8, we have:

C(12,8)=\frac{12!}{8!(12-8)!_{}}=\frac{12\cdot11\cdot10\cdot9\cdot8!}{8!\cdot4!}=\frac{12\cdot11\cdot10\cdot9}{4\cdot3\cdot2}=495

So there are 495 ways.

B.

If she wants to arrange the 12 photos, the total number of ways is given by the factorial of 12:

12!=12\cdot11\cdot10\cdot9\cdot8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2=479001600

There are 479,001,600 ways.

C.

Since 10 photos already have specific places, we need to calculate the number of ways to arrange the other two photos in the two remaining places.

In this case, there are only 2 ways of organizing the remaining two photos:

Photo 1 first, photo 2 last, or photo 1 last and photo 2 first.

6 0
1 year ago
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