First you would isolate (7m) by subtracting 4 from both sides:
4 + 7m - 4 = 5 - 4
This would leave you with:
7m = 1
Then you would isolate m by dividing both sides by 7:
7m/7 = 1/7
Your final answer:
m = 1/7
Answer:
Truck can safely carry <em>2310 pounds </em> of cargo.
Step-by-step explanation:
Given the safety limit of weight to cross the bridge safely is 4 tons.
1 ton is equal to 2000 pounds.
so, 4 tons are equal to 2000
4 = 8000 pounds
Now, given that
weight of empty truck and driver = 5690 pounds
To find:
Weight of cargo that the truck can safely carry ?
Solution:
Total weight of the truck is actually the combined weight of the empty truck, the drive and the cargo carried in it.
So, Total Weight allowed = 8000 pounds = 5690 pounds + Weight of Cargo
Weight of Cargo = 8000 - 5690 pounds
Weight of Cargo = <em>2310 pounds</em>
Truck can safely carry <em>2310 pounds </em> of cargo.
<span>f(x)=3-2x
</span><span>f(8)=3-2(8) = 3 -16 = -13
</span><span>g(x)=1/x+5
</span><span>g(8)=1/8+5 = 1/8 + 40/8 = 41/8
</span><span>[f/g](8) = -13 / (41/8) = -13 * (8/41) = -104/41 = -2 22/41</span>
the following graph represents f(X)=X+2