Let r = (t,t^2,t^3)
Then r' = (1, 2t, 3t^2)
General Line integral is:

The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector


Fortunately, this simplifies nicely with a 'u' substitution.
Let u = 1+4t^2 +9t^4
du = 8t + 36t^3 dt

After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
Divide 3 by 8! So your answer would be 0.375! :)
Answer:
6
Step-by-step explanation:
84 = 3 x 28
56 = 2 x 28
Minimum number of square plot, each square is 28 x 28
the number is 3 x 2 = 6
In the box where 'Tails' and 'Not six' is, write 68. Then right under that you ADD 50 and 68. Then under 'Six' and 'Tail' you MINUS 79 and 68. And finally under that one you ADD 21 and the answer you got.
So in the end this is how it should look:
The original function f(x) = 2x+3.
And the transformed function is g(x) = 2x+4.
We can see that if we add 1 into function f(x), we get
f(x) +1 or 2x+3+1 = 2x+4.
<h2>
So, 1 is being added in original function f(x) and we get g function g(x) = 2x+4.</h2>
<em>According to rules of transformations, when we add some number k in the given function, it move k units up and if we subtract k from given function, it move k units down.</em>
<h3>Therefore, correct option is B option.</h3><h3>B. translation 1 unit up.</h3>