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2 years ago

Is it proportional or non proportional

Mathematics

1 answer:

natta225 [31]2 years ago

6 0

Answer:

proportional

Step-by-step explanation:

13/2=6.5

19.5/3=6.5

26/4=6.5

32.5/5=6.5

so if all equal the same they are proportional

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If a= -3 what is 3a^2

trapecia [35]

Answer:

Step-by-step explanation:

If a= -3 what is 3a^2 = 27

4 0

2 years ago

The value V of a certain automobile that is t years old can be modeled by V(t) = 14,651(0.81). According to the model, when will

lakkis [162]

Answer:

a) The car will be worth $8000 after 2.9 years.

b) The car will be worth $6000 after 4.2 years.

c) The car will be worth $1000 after 12.7 years.

Step-by-step explanation:

The value of the car after t years is given by:

$V(t) = 14651(0.81)^{t}$

According to the model, when will the car be worth V(t)?

We have to find t for the given value of V(t). So

$V(t) = 14651(0.81)^{t}$

$(0.81)^t = \frac{V(t)}{14651}$

$\log{(0.81)^{t}} = \log{(\frac{V(t)}{14651})}$

$t\log{(0.81)} = \log{(\frac{V(t)}{14651})}$

$t = \frac{\log{(\frac{V(t)}{14651})}}{\log{0.81}}$

(a) $8000

V(t) = 8000

$t = \frac{\log{(\frac{8000}{14651})}}{\log{0.81}} = 2.9$

The car will be worth $8000 after 2.9 years.

(b) $6000

V(t) = 6000

$t = \frac{\log{(\frac{6000}{14651})}}{\log{0.81}} = 4.2$

The car will be worth $6000 after 4.2 years.

(c) $1000

V(t) = 1000

$t = \frac{\log{(\frac{1000}{14651})}}{\log{0.81}} = 12.7$

The car will be worth $1000 after 12.7 years.

5 0

2 years ago

HELP ASAP

zavuch27 [327]

2rd one I could be wrong tho

6 0

2 years ago

Read 2 more answers

Ginger's cat gave birth to a kitten that weighed 3 3/8 ounces when it was born. On the day Ginger sold the kitten to its new own

KiRa [710]

The kitten grew 2.12 lbs

8 0

3 years ago

Read 2 more answers

A telemarketer earns $150 a week plus $2 for each call that results in sale. Last week she earned a total of $204. How many of h

cluponka [151]

Answer:

27 calls

Step-by-step explanation:

Let T(x) represent total sales.

Then T(x) = $150 + ($2/call)x, where x is the number of calls made.

If T(x) = $204, we can solve for x, the number of calls made:

$204 = $150 + ($2/call)x, or

$ 54

----------- = 27 calls

$2/call

8 0

3 years ago