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Natalka [10]
3 years ago
5

A cube-shaped box has a volume of 27 cubic inches. If the box is packed full of cubes with edge lengths of 1 inch, how many cube

s can fit along one side of the
box?
Mathematics
1 answer:
iogann1982 [59]3 years ago
8 0

Answer:

9 along one side.

Step-by-step explanation:

This question may be a bit tricky.

The side should mean the entire side, not just along the bottom edge.

The bottom row will have three 1-inch cubes. Three more in a middle row, and three more on top of that. That is a total of nine on that side.

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Consider the equation x^2=36 which of the following statements below are true
Mnenie [13.5K]

Answer:

6

Step-by-step explanation:

6 to the power of 2 equals 6

It would look like 6*6

8 0
3 years ago
Read 2 more answers
Make n the subject of m= 4n-gn+1
Misha Larkins [42]

Answer:

n = (m-1)/(4-g)

Step-by-step explanation:

m= 4n-gn+1

Subtract 1 from each side

m-1= 4n-gn+1-1

m-1 = 4n -gn

Factor out n

m-1 = n(4-g)

Divide each side by (4-g)

(m-1)/(4-g) =  n(4-g)/(4-g)

(m-1)/(4-g) =  n

n = (m-1)/(4-g)

6 0
3 years ago
Read 2 more answers
In ΔOPQ, o = 58 cm, q = 13 cm and ∠Q=52°. Find all possible values of ∠O, to the nearest degree.
PSYCHO15rus [73]

Answer:

There is no possible triangles

Step-by-step explanation:

\frac{\sin A}{a}=\frac{\sin B}{b}

a

sinA

​  

=  

b

sinB

​  

 

From the reference sheet (reciprocal version).

\frac{\sin O}{58}=\frac{\sin 52}{13}

58

sinO

​  

=  

13

sin52

​  

 

Plug in values.

\sin O=\frac{58\sin 52}{13}\approx 3.5157403

sinO=  

13

58sin52

​  

≈3.5157403O=\sin^{-1}(3.5157403)= \text{ERROR}

O=sin  

−1

(3.5157403)=ERROR

Sine cannot be greater than 1.

{No Possible Triangles}

No Possible Triangles

{}

{}

7 0
3 years ago
What is are if a rectangle of length of 5 and width of 3x-5y+6What is the area of a rectangle with a length of 5 and a width of
lawyer [7]

The area of rectangle is 15x - 25y + 30 sqaure units

<em><u>Solution:</u></em>

Given that, a rectangle with a length of 5 and a width of 3x - 5y + 6

To find: Area of rectangle

<em><u>The area of rectangle is given by formula:</u></em>

Area = length \times width

From given,

Length = 5

Width = 3x - 5y + 6

<em><u>Substituting the values in formula, we get,</u></em>

Area = 5 \times (3x - 5y + 6)\\\\\text{Multiply 5 with each term inside the bracket }\\\\Area = 5(3x) -(5)(5y) +5(6)\\\\\text{Simplify the above expression }\\\\Area = 15x -25y + 30

Thus area of rectangle is 15x - 25y + 30 sqaure units

6 0
3 years ago
HELPPPPPPPPPPPPPP!!!!!!
enot [183]

Answer:

I love and want to see you in your underwear

Step-by-step explanation:

4 0
3 years ago
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