Find the distance between the points H and C. A) 0 B) 2 C) 4 D) 8

Hurry please btw this not my laptop

icang [17]

Answer:

16x X 44 squared

Step-by-step explanation:

8 0

3 years ago

A random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6. A random sample of 17 su

Sladkaya [172]

Answer:

We conclude that there is no difference in potential mean sales per market in Region 1 and 2.

Step-by-step explanation:

We are given that a random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6.

A random sample of 17 supermarkets from Region 2 had a mean sales of 78.3 with a standard deviation of 8.5.

Let $\mu_1$ = mean sales per market in Region 1.

$\mu_2$ = mean sales per market in Region 2.

So, Null Hypothesis, $H_0$ : $\mu_1-\mu_2$ = 0 {means that there is no difference in potential mean sales per market in Region 1 and 2}

Alternate Hypothesis, $H_A$ : > $\mu_1-\mu_2\neq$ 0 {means that there is a difference in potential mean sales per market in Region 1 and 2}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about population standard deviations;

T.S. = $\frac{(\bar X_1 -\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+ {\frac{1}{n_2}}} }$ ~ $t__n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean sales in Region 1 = 84

$\bar X_2$ = sample mean sales in Region 2 = 78.3

$s_1$ = sample standard deviation of sales in Region 1 = 6.6

$s_2$ = sample standard deviation of sales in Region 2 = 8.5

$n_1$ = sample of supermarkets from Region 1 = 12

$n_2$ = sample of supermarkets from Region 2 = 17

Also, $s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $s_p=\sqrt{\frac{(12-1)\times 6.6^{2}+(17-1)\times 8.5^{2} }{12+17-2} }$ = 7.782

So, the test statistics = $\frac{(84-78.3)-(0)}{7.782 \times \sqrt{\frac{1}{12}+ {\frac{1}{17}}} }$ ~ $t_2_7$

= 1.943

The value of t-test statistics is 1.943.

Now, at a 0.02 level of significance, the t table gives a critical value of -2.472 and 2.473 at 27 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that there is no difference in potential mean sales per market in Region 1 and 2.

6 0

3 years ago

Prove that angle W is congruent to angle Y with a two column proof.

iren2701 [21]

Statement 1: WXYZ is a kite

Reason 1: Given

Statement 2: WX = XY and WZ = YZ

Reason 2: Definition of a kite

Statement 3: XZ = XZ

Reason 3: Reflexive property

Statement 4: Triangle WXZ = Triangle YXZ

Reason 4: SSS Congruence

Statement 5: Angle W = Angle Y

Reason 5: CPCTC

-------------------------------------------------------------------------

Extra notes:

* A kite is a quadrilateral that has two pairs of adjacent congruent sides. In this case, WX and XY is one pair of congruent sides that are adjacent (ie next to each other). So that's why WX = XY. Similarly, WZ = YZ is the second pair of adjacent congruent sides.

* Draw in a segment from point X to point Z to help form two triangles. The two triangles are congruent as proven in statement 4. One triangle is a reflection over the line XZ to get the other triangle.

* Due to this reflection, angle W reflects over line XZ to get angle Y. Proving that angle W = angle Y

* SSS means "side side side", basically saying "you use three pairs of congruent sides to prove two triangles congruent".

* The acronym CPCTC stands for "corresponding parts of congruent triangles are congruent"

4 0

3 years ago

Eddie drilled into a piece of wood and I joist to attach them if he drilled 3 inches in the wood was one and 1 1/3 inches thick

NARA [144]

Let JD = Distance drilled in joist
JD = 3 - 1 1/3 
JD = 9/3 - 4/3 
========================== 
JD = 5/3 or 1 2/3 in ◄ Ans

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

7 0

3 years ago

Michael has $15 and wants to buy a combination of school lunches to feed at least three classmates. A sandwich costs $2, and hot

Morgarella [4.7K]

A. Solution set is in the attachment (dark green shading in the middle)

B. Yes, 2(5) + 3(1) ≤ 15; 13 is less than or equal to 15

5 + 1 > 3, 6 is greater than 3

C. (4, 2) means that he buys 4 sandwiches and 2 hot lunches

7 0

3 years ago