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stellarik [79]
4 years ago
7

With a certain tailwind, an airplane reached its destination, 630 miles away, in 1 1/2 hours. Flying

Mathematics
1 answer:
soldi70 [24.7K]4 years ago
7 0

Answer:

V=390mph and W=30mph

Step-by-step explanation:

Let V be the speed of the airplane and W the speed of the wind.

We have two travels and the formula v=d/t:

V+W=630miles/1.5hr (With the wind)

V-W=630miles/1.75hr (agains the wind)

Clear V from the 1st equation. V=(630/1.5)-W

And replace it into the 2nd equation:

(630/1.5)-W-W=630/1.75

420-2W=360

420-360=2W

W = 60/2

W = 30mi/hr is the wind speed.

Now, we can find V using one equation:

V=(630/1.75)+30 = 360+30

V=390mi/hr is the speed of the airplane.

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I hope this helps you




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6 0
3 years ago
Solve this system for brainliest answer!!!<br><br> 3.75x+4y=2,160<br> x+y=550
djyliett [7]
First solve the second equation to equal x.

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Subtract y from both sides.

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Put this into the first equation in place of x.

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Multiply everything in the parenthesis by 3.75

2062.5 - 3.75y + 4y = 2160

Combine like terms.

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Subtract 2062.5 from both sides.

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Divide 0.25 on both sides.

y = 390

Put this into the second equation in place of y.

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6 0
3 years ago
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Allushta [10]
The correct answer is: H.
4 0
3 years ago
What is the effect on the graph of f(x) = x2 when it is transformed toh(x) = 3x2 + 12?A. The graph of f(x) is horizontally compr
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1 year ago
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Gala2k [10]

Answer:

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