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stellarik [79]
4 years ago
7

With a certain tailwind, an airplane reached its destination, 630 miles away, in 1 1/2 hours. Flying

Mathematics
1 answer:
soldi70 [24.7K]4 years ago
7 0

Answer:

V=390mph and W=30mph

Step-by-step explanation:

Let V be the speed of the airplane and W the speed of the wind.

We have two travels and the formula v=d/t:

V+W=630miles/1.5hr (With the wind)

V-W=630miles/1.75hr (agains the wind)

Clear V from the 1st equation. V=(630/1.5)-W

And replace it into the 2nd equation:

(630/1.5)-W-W=630/1.75

420-2W=360

420-360=2W

W = 60/2

W = 30mi/hr is the wind speed.

Now, we can find V using one equation:

V=(630/1.75)+30 = 360+30

V=390mi/hr is the speed of the airplane.

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