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dimaraw [331]
3 years ago
9

A grocery store will only accept yellow onions that are at least 2.75 in. in diameter. A grower has a crop of onions with diamet

ers that are normally distributed, with a mean diameter of 3.25 in. and a standard deviation of 0.25 in. What percent of the onions will be accepted by the grocery store?
Mathematics
2 answers:
maksim [4K]3 years ago
8 0
Imagine (or draw) a standard normal curve.  Draw a vertical line through the center of this curve, and mark it 3.25 inches.  This is the mean diameter.  Next, draw vertical lines to represent these sums:  3.25 plus .25, or 3.50 inches; 3.25 less .25, or 3.00 inches, and 3.25 less .50 inches, or 2.75 inches.

Note that 2.75 inches is 2 standard deviations below the mean:  That's 2.75 inches less twice 0.25 inches, or 2.75 = 3.25 inches less 2(0.25) inches.

onions with diameters less than 2.75 are rejected; onions with diameters greater than 2.75 inches are accepted.

Find the area to the LEFT of 2.75 inches.  In other words, find the area to the left of 2 standard deviations below the mean.

I would use the Empirical Rule here:  "68% of data is within 1 standard dev. of the mean; 95% is within 2 standard dev. of the mean.

This tells us that the area to the left of 2.75 inches or -2 standard deviations is 0.025 (half of 0.050).  Subtract this from 1.000; you'll get 0.975.  This means that 97.5% of the onions will prove to be acceptable, whereas 2.5% will be rejected because they are less than 2.75 inches in diameter.

You could also use a table of z-scores to do this:  Determine from the table the area under the std. normal curve to the left of -2 std. dev.  Again, this comes out to 0.025, meaning that the area to the right of -2 std. dev is 0.975.
kykrilka [37]3 years ago
8 0

Answer:

97.72%

Step-by-step explanation:

mean diameter of 3.25 in. and a standard deviation of 0.25

WE need to find P(x>2.75)

P(x>2.75)= 1- P(x=2.75)

Lets use z-score formula

z = \frac{x-mean}{standard \ deviation}

z = \frac{2.75-3.25}{0.25}=-2

Now we use z-score table and find the value when z=-2

The value is  0.0228

P(x>2.75)= 1- P(x=2.75)

P(x>2.75)= 1- 0.0228 = 0.9772

To get percentage we multiply by 100

0.9772 * 100 = 97.72%


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