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3 years ago

PLZ HELP!

Mathematics

1 answer:

Sladkaya [172]3 years ago

3 0

Answer:

Step-by-step explanation:

hey i think its A)2/3

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Timmy is on a 2100 mile trip across the country. Over the last 12 hours of driving Timmy has traveled 720 miles. If he continues

kondor19780726 [428]

Answer:

23 hours

Step-by-step explanation:

So here we are trying to calculate Time which is Distance divided by Speed

Time = $\frac{Distance}{Speed}$

Firstly, we have to calculate the Speed which is = $\frac{720}{12}$ = 60

This means that the speed is 60 miles per hour or 60 mph.

Then to find the total time we take the Distance and divide it by the Speed:

$\frac{2100}{60}$ = 35

So this means that his total trip took 35 hours so lets subtract 12 hours to get how many more hours: 35 - 12 = 23 hours

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3 years ago

if the number of different schedules is represented by three consecutive even integers, what is the expression for that total nu

Reika [66]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Marilyn earns $150 per month delivering newspapers plus $7 an hour babysitting. If she wants to earn at least $300 this month, h

Firdavs [7]

300-150=150 so 150 divided by 7= at lease 42 hours

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4 years ago

Read 2 more answers

HELP! 15 POINTS!

Brut [27]

It's pretty easy to go through the choices and none has a[2]=-36 and a[5]=2304. Something's probably wrong with the way the question is typed, but I will answer what's written.

$a_n = a + (n-1) d$

$a_2 = -36 = a + d$

$a_5 = 2304 = a + 4d$

Subtracting,

$2340 = 3d$

$d = 2340/3 = 780$

$a = -36 - d = -36 - 780 = -816$

Answer: a[n] = -816 + 780(n-1) which is none of the above

Check:

$a_2 = -816 + 780= -36 \quad\checkmark$

$a_5 = -816 + 780(4) = 2304 \quad\checkmark$

8 0

3 years ago

The sugar content of the syrup in canned peaches is normally distributed. A random sample of n=25 cans yields a sample standard

egoroff_w [7]

Answer:

99% one-sided lower confidence bound = 26.77

Step-by-step explanation:

We have to calculate a 99% one-sided lower confidence bound for the population variance.

The sample size is n=25.

The degrees of freedom are then:

$df=n-1=25-1=24$

The critical value of the chi-square for this confidence bound is:

$\chi^2_{0.01, \,24}=42.98$

Then, the lower confidence bound can be calculated as:

$LB=\dfrac{(n-1)s^2}{\chi^2_{0.01,24}}=\dfrac{24\cdot(6.9)^2}{42.98}=\dfrac{1,142.64}{42.68}=26.77$

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3 years ago