Check the picture below.
the area of the triangle whose base is AC and height is BD, is the same area of the triangle whose base is AB and altitude is BC, namely
![A=\cfrac{1}{2}(\stackrel{b}{6})(\stackrel{h}{6})\implies 18](https://tex.z-dn.net/?f=A%3D%5Ccfrac%7B1%7D%7B2%7D%28%5Cstackrel%7Bb%7D%7B6%7D%29%28%5Cstackrel%7Bh%7D%7B6%7D%29%5Cimplies%2018)
Step-by-step explanation:
Hey there!
The equation of a st.line passing through points (4,5) and (7,3) is;
![(y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)](https://tex.z-dn.net/?f=%28y%20-%20y1%29%20%3D%20%20%5Cfrac%7By2%20-%20y1%7D%7Bx2%20-%20x1%7D%20%28x%20-%20x1%29)
<u>Put</u><u> </u><u>all values</u><u>. </u>
<u>
</u>
<u>Simplify</u><u> </u><u>it</u><u>. </u>
<u>
</u>
<u>
</u>
<u>
</u>
<u>
</u>
<u>Therefore the</u><u>required</u><u> </u><u>equation</u><u> </u><u>is</u><u> </u><u>2</u><u>x</u><u>+</u><u>3</u><u>y-23</u><u>=</u><u>0</u><u>.</u>
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
not really but if you know how to do punit squares its basically the same
Step-by-step explanation:
Answer:
25/81.
Step-by-step explanation:
(27/8)^-4/3
= 8^4/3 / 27^4/3
= (∛8)^4 / (∛27)^4
= 16 / 81
(64/125)^-2/3
= (125)^2/3 / (64)^2/3
= (∛125)^2 / (∛64)^2
= 5^2 / 4^2
= 25/16
So the answer is
16/81 * 25/16
= 25/81.
Answer:
F(x)=h(x)-8
I think
Step-by-step explanation: