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DerKrebs [107]
3 years ago
14

What is three to the third power times two to the fourth power equal?

Mathematics
1 answer:
rewona [7]3 years ago
7 0
The answer is 43 because 3*3*3=27 and 4*4=16
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Let f(x) = -4x + 7 and g(x) = 10x - 6 find f(g(x))
max2010maxim [7]
F(x) = -4x + 7
g(x) = 10x - 6

f(g(x)) = -4(10x - 6) + 7
f(g(x)) = -4(10x) + 4(6) + 7
f(g(x)) = -40x + 24 + 7
f(g(x)) = -40x + 31
7 0
3 years ago
Read 2 more answers
There is one error in one of five blocks of a program. To find the error, we test three randomly selected blocks. Let X be the n
marusya05 [52]
Probability(error in one block)= 1/5
<span>Probability(error in 3 blocks)= 3*(1/5)= 0.6</span>

Let, 
     0 = No error
<span>     1 = error
</span>Hence.
E(x) = 0.4 x 0 x+0.6 + 1 
        = 1.6
6 0
3 years ago
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Please help me its help.
IgorLugansk [536]

The answer will be 81.

Step-by-step explanation:

just multiple by 3

8 0
2 years ago
Read 2 more answers
What is a number <br> between 1.63 and 1.64
Oksi-84 [34.3K]

Answer:

1.635

Step-by-step explanation:

6 0
3 years ago
How do i calculate? All the way to s_75. It’s so long
mina [271]

Answer:

  -675

Step-by-step explanation:

The sum can be broken into parts that you know. Here, one of those parts is the sum of numbers 1 to n. That sum is given by n(n+1)/2.

\displaystyle S_{75}=\sum\limits_{n=1}^{75}{(67-2n)}=\sum\limits_{n=1}^{75}{67}-2\sum\limits_{n=1}^{75}{n}\\\\=75\cdot 67-2\dfrac{75(75+1)}{2}=75(67-76)\\\\=\bf{-675}

__

Another way to do this is to realize the sequence of numbers is an arithmetic sequence with a first term of 65 and a last term of 67-2·75 = -83.

The sum of an arithmetic sequence is found by multiplying the number of terms by their average value. Their average value is the average of the first and last terms.

The average value of those 75 terms is (65 +(-83))/2 = -9, so their sum is ...

  75(-9) = -675

7 0
3 years ago
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