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4 years ago

How is the numeral 55.12 written in words?

Mathematics

2 answers:

masha68 [24]4 years ago

6 0

Fifty-five. twelve. Hope this helps.

Ivan4 years ago

4 0

Fifty-five and twelve hundreths

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Find the equation in standard form of the line with slope

Serhud [2]

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ 5}}\quad ,&{{ 7}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{7}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-7=\cfrac{7}{2}(x-5)\implies y-7=\cfrac{7}{2}x-\cfrac{35}{2}
\\\\\\
y=\cfrac{7}{2}x-\cfrac{35}{2}+7\implies \stackrel{standard~form}{-\cfrac{7}{2}x+y=-\cfrac{21}{2}}$

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3 years ago

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sattari [20]

Answer:

7/3

Step-by-step explanation:

7 0

3 years ago

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I. There is a gap in the Potato Chips group

topjm [15]

Answer:

C) I and II

There is a gap in the Potato Chips group for the stem "14" and the Tortilla Chips group for the stem "12"

4 0

3 years ago

Someone tell me what 8x+ 7 isss

Lesechka [4]

This expression is not factorable which means the answer is 8x+7

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4 years ago

Six measurements were made of the magnesium ion concentration (in parts per million, or ppm) in a city's municipal water supply,

myrzilka [38]

Answer:

$163.83-4.03\frac{20.094}{\sqrt{6}}=130.77$

$163.83+4.03\frac{20.094}{\sqrt{6}}=196.89$

So on this case the 99% confidence interval would be given by (130.77;196.89)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data: 175 177 175 180 138 138

We can calculate the mean and the deviation from these data with the following formulas:

$\bar X= \frac{\sum_{i=1}^n x_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}$

$\bar X=163.83$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=20.093 represent the sample standard deviation

n=6 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=6-1=5$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,5)".And we see that $t_{\alpha/2}=4.03$

Now we have everything in order to replace into formula (1):

$163.83-4.03\frac{20.094}{\sqrt{6}}=130.77$

$163.83+4.03\frac{20.094}{\sqrt{6}}=196.89$

So on this case the 99% confidence interval would be given by (130.77;196.89)

7 0

3 years ago