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galina1969 [7]
3 years ago
11

24 tenths - 1 one 3 tenths

Mathematics
1 answer:
pychu [463]3 years ago
6 0
Are you saying 1\3 teeth?
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Fill in the blank:<br> 5/7 of ... is 1/7
Sveta_85 [38]
5/49

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4 0
3 years ago
Find the equation of a line that have the same slope as Y= 6-3x and the same Y intercept as Y=-7X -10
choli [55]

Answer:

y = -3x -10

Step-by-step explanation:

6 0
3 years ago
The swimming pool is open when the high temperature is higher than 20^\circ\text{C}20 ? C20, degree, C. Lainey tried to swim on
Svetlanka [38]

Answer:

30-3d\leq 20

Step by step explanation:

Let d represent the rate of temperature decrease in degrees Celsius per day from Monday to Thursday.  

As temperature decreased at a constant rate in the next 3 days, so the rate of temperature will decrease 3d degree Celsius in 3 days.  

We are told that the pool was open on Monday. The high temperature was 30^{\circ}{\text{C} on Monday. So the decrease in temperature from Monday to Thursday will be 30-3d.

We have been given that the swimming pool is open when the high temperature is higher than 20^{\circ}{\text{C}.

As the pool was closed on Thursday. This means that temperature on Thursday was less than or equal to 20 degree Celsius. We can represent this information in an inequality as:

30-3d\leq 20

Therefore, the inequality 30-3d\leq 20 can be used to determine the rate of temperature decrease in degrees Celsius per day, d, from Monday to Thursday.

5 0
4 years ago
Simplify.<br> 4/x^2-35 - 1/x+5
Oksana_A [137]
If I understand your question well, I suppose you mean \frac{4}{ x^{2} -35} -  \frac{1}{x+5}
\frac{4}{ x^{2} -35} - \frac{1}{x+5} =  \frac{4}{(x+5)(x-7)}- \frac{1}{x+5} \\ = \frac{1}{x+5}( \frac{4}{x-7}-1) \\ = \frac{1}{x+5}( \frac{4}{x-7}- \frac{x-7}{x-7}) \\ = \frac{1}{x+5}( \frac{4-x+7}{x-7}) \\ = \frac{1}{x+5}( \frac{11-x}{x-7}) \\ = \frac{11-x}{ x^{2} -35}
6 0
3 years ago
If f(x)=3<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="late
Anvisha [2.4K]

Answer:

\sf f(-3) = 23

<u>given:</u>

\sf f(x) = 3x^2 -4

to find the output, replace x with the given integer.

solve:

\sf f(-3) = 3(-3)^2 -4

\sf f(-3) = 3(9) -4

\sf f(-3) = 27 -4

\sf f(-3) = 23

5 0
2 years ago
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