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3 years ago

What is 16 thirds as mixed number

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

6 0

16/3
=
5 1/3

qsjhqjvejh

OLEGan [10]3 years ago

3 0

It is 5 and 1/3 ! yes she got they got it right⬆️

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Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the co

jeka57 [31]

Answer:

<h2>A. The series CONVERGES</h2>

Step-by-step explanation:

If $\sum a_n$ is a series, for the series to converge/diverge according to ratio test, the following conditions must be met.

$\lim_{n \to \infty} |\frac{a_n_+_1}{a_n}| = \rho$

If $\rho$ < 1, the series converges absolutely

If $\rho > 1$ , the series diverges

If $\rho = 1$ , the test fails.

Given the series $\sum\left\ {\infty} \atop {1} \right \frac{n^2}{5^n}$

To test for convergence or divergence using ratio test, we will use the condition above.

$a_n = \frac{n^2}{5^n} \\a_n_+_1 = \frac{(n+1)^2}{5^{n+1}}$

$\frac{a_n_+_1}{a_n} = \frac{{\frac{(n+1)^2}{5^{n+1}}}}{\frac{n^2}{5^n} }\\\\ \frac{a_n_+_1}{a_n} = {{\frac{(n+1)^2}{5^{n+1}} * \frac{5^n}{n^2}\$

$\frac{a_n_+_1}{a_n} = {{\frac{(n^2+2n+1)}{5^n*5^1}} * \frac{5^n}{n^2}\\$

aₙ₊₁/aₙ =

$\lim_{n \to \infty} |\frac{ n^2+2n+1}{5n^2}| \\\\Dividing\ through\ by \ n^2\\\\\lim_{n \to \infty} |\frac{ n^2/n^2+2n/n^2+1/n^2}{5n^2/n^2}|\\\\\lim_{n \to \infty} |\frac{1+2/n+1/n^2}{5}|\\\\$

note that any constant dividing infinity is equal to zero

$|\frac{1+2/\infty+1/\infty^2}{5}|\\\\$

$\frac{1+0+0}{5}\\ = 1/5$

$\rho = 1/5$

Since The limit of the sequence given is less than 1, hence the series converges.

5 0

2 years ago

Find the values of the variables for each quadrilateral.

kondaur [170]

Correct answer is the 3rd one.

8 0

2 years ago

Enter the value of x that makes the equation 3x + 4 + 2x + 2 = -24

lesya692 [45]

Answer:

x = -6

Step-by-step explanation:

Combine like terms.

5x + 6 = -24

Subtract 6 from both sides.

5x = -30

Divide by 5 on both sides.

x = -6

3 0

2 years ago

Read 2 more answers

By using a number line, arrange each of the each of the following in descending order (a) 4 29upon 33, -2.365,5.5,-3 upon 4 (b)

Sergeeva-Olga [200]

The arrangement of the numbers in descending order (largest to smallest) are as follows;

a). 5.5, 4, 29/33, -3/4, -2.365
b). 10, 5.855, 5/8, 1/2 -2π, -8

<h3>What is the arrangement of the numbers in descending order in each case?</h3>

It follows from convention that the positive numbers are larger than negative numbers and hence, should appear before negative numbers when the arrangement is in descending order.

Consequently, the numbers can be evaluated and arranged as in the answer above with positive numbers increasing rightwards and negative numbers decreasing leftward of 0 on the number line.