1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sergiy2304 [10]
3 years ago
8

You are getting a line-up ready for a school kickball game. You have 4 girls and 4 boys. The rules state each child must kick th

e same number of times and alternate girl-boy or boy-girl. How many ways can a line-up be made for one round of kicking?

Mathematics
1 answer:
tatuchka [14]3 years ago
6 0

Answer:

So the total number of  ways  in which the line-up can be made is 2880 ways.

Step-by-step explanation:

Please refer the attached figure for reference.

Now, there are 4 girls and 4 boys and  we are asked to find the number of  ways in which they can be lined up alternately.

That basically means that there should be a boy next to a girl in the arrangement.

So, at first we will arrange the 4 boys ( at B positions in the figure ), and that can be done in 4! ways.

Now, there are 5 positions ( 5 blue dots in the figure ), which can be taken by 4 girls, in such a way that the boys and girls are placed alternately.

So, 4 girls can take 5 positions in 5_P__4 ways.

So the total number of  ways  in which the line-up can be made = 4! x 5_P__4 = 24 x 120 = 2880 ways.

You might be interested in
2z - 6 = 2(2 + 2) - 10
Blababa [14]

Answer:

z=2

Step-by-step explanation:

2z-6=2(2+2)-10  Distribute.

2z-6=4+4-10      Combine like terms.

2z-6=-2              Add 6 on both sides.

   <u>+6 +6</u>

2z=4                   Divide by 2 on both sides.

<u>/2 /2</u>

z=2

Hope this helps! Have a great day ^^

6 0
3 years ago
A school chorus has 90 sixth-grade students and 75 seventh-grade students. The music director wants to make groups of performers
Tresset [83]

Answer:

The music director can form a total of 15 groups

6 Sixth grade students per group

5 Seventh grade students per group

Step-by-step explanation:

Sixth grade students = 90

Seventh grade students = 75

Find the highest common factor of 75 and 90

90 = 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90.

75 = 1, 3, 5, 15, 25, 75

The highest common factor of 75 and 90 is 15

Therefore, the music director can form a total of 15 groups

Sixth grade students per group = 90 / 15

= 6 Sixth grade students per group

Seventh grade students per group = 75 / 15

= 5 Seventh grade students per group

3 0
3 years ago
Pls help me with this I have 5 minutes to do this I will give brainleast plzz
weeeeeb [17]

Answer:

The answer for the first one is 1/2.

The answer for the second one is -1/1

Step-by-step explanation:

Hope that helps you :)

8 0
3 years ago
2x+5y=46<br> 5x+3y=58<br><br> what are the x and y values
nadya68 [22]
(X,y)=(8,6)
Step by step explanation:
3 0
3 years ago
Giving away 50 points because why not?
pychu [463]
Ummm yes please! Thanks so much!!! Merry Christmas

╰(*´︶`*)╯♡
6 0
3 years ago
Read 2 more answers
Other questions:
  • PLEASE HELP !!!! What is the slope of the line passing through the points (1, −5)(1, −5) and (4, 1)(4, 1)?
    9·1 answer
  • Which values complete the function?<br> f(x) = (x-__ )(x+___)
    10·1 answer
  • I just need question a I don’t understand it and it would mean a lot if you can help me
    5·2 answers
  • Pls someone answer quickly!!!!!
    13·1 answer
  • Amaria and her Mom want to use fewer boxes and put different of brownies into the same box. How many whole boxes do they fill? W
    13·1 answer
  • How do you solve this equation 1/3(x+1)+2x=2.
    15·1 answer
  • How many feet are in 219inches
    13·2 answers
  • Can you help me image is here which 2 Should I drag
    8·2 answers
  • What's the equivalent fraction of 3/7
    12·2 answers
  • Ryan and Sheila are preparing to get married. Sheila has a car payment of $297.00 per month, which is 9% of her monthly income.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!