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sergiy2304 [10]
3 years ago
8

You are getting a line-up ready for a school kickball game. You have 4 girls and 4 boys. The rules state each child must kick th

e same number of times and alternate girl-boy or boy-girl. How many ways can a line-up be made for one round of kicking?

Mathematics
1 answer:
tatuchka [14]3 years ago
6 0

Answer:

So the total number of  ways  in which the line-up can be made is 2880 ways.

Step-by-step explanation:

Please refer the attached figure for reference.

Now, there are 4 girls and 4 boys and  we are asked to find the number of  ways in which they can be lined up alternately.

That basically means that there should be a boy next to a girl in the arrangement.

So, at first we will arrange the 4 boys ( at B positions in the figure ), and that can be done in 4! ways.

Now, there are 5 positions ( 5 blue dots in the figure ), which can be taken by 4 girls, in such a way that the boys and girls are placed alternately.

So, 4 girls can take 5 positions in 5_P__4 ways.

So the total number of  ways  in which the line-up can be made = 4! x 5_P__4 = 24 x 120 = 2880 ways.

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Answer:

17

Step-by-step explanation:

Number of students in soccer club, n(S) = 50

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n(S \cup A\cup G) = 100

n(S \cap A\cap G) = 9

n(S \cap A) = 20

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Formula:

n ( A ∪ B ∪ C ) =  n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )

Putting the values:

100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9

100 = 112 + n(G) - 84

n(G) = 72

Number of students in gaming club only = n(G) - n(G \cap S) - n(A \cap G) + n(S \cap A\cap G)

= 72 - 35 - 29 + 9

= <em>17</em>

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