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3 years ago

6

Yo can someone help me out

2 answers:

amid [387]3 years ago

8 0

Answer:

x = 21

Step-by-step explanation:

corresponding sides in similar polygons are proportional:

set a proportion: BC/FK = CA/KJ => 18/6 = x/7 => x = 18 × 7 ÷ 6 = 21

weqwewe [10]3 years ago

4 0

X=21 I think maybe yeah

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Two pieces of lengths 13/3 m and 3/5 m are cut off from a rope 15

garri49 [273]

Hello there! ;) The way you solve this type of problem is you must find common denominators. So simplify 13/3= 4 1/3. So we can do 1/3*5/5=5/15. Next we must do 3/5*3/3= 9/15. So add 5/15+9/15= 14/15. And add the 4+ 14/15= 4 14/15. So then you must subtract 15 - 4 14/15= 10 1/15 I believe. I believe 10 1/15 is the remainder of the rope. You might want to check in with someone else though.

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4 years ago

Find the area of the kite p=17 q =15.3

Semenov [28]

Answer:

$\large\boxed{A=130.05}$

Step-by-step explanation:

The formula of an area of a kite:

$A=\dfrac{pq}{2}$

p, q - diagonals

We have p = 17 and q = 15.3. Substitute:

$A=\dfrac{(17)(15.3)}{2}=\dfrac{260.1}{2}=130.05$

3 0

3 years ago

Which complex number has a distance of 17 from the origin on the complex plane?

Virty [35]

Answer:

None of the options are correct.

Step-by-step explanation:

Let the complex number is a + ib

Given distance from origin = 17 units

Now, by distance formula distance of a point from the origin =

$17 = \sqrt{(x)^{2} + (y)^{2} }$

1) <u>Check for 2 + 15 i</u>

here, $\sqrt{15^2 + 2^2} = \sqrt{225 + 4} = \sqrt{229}$ ≠ 17

2)<u> Check for 17 + i</u>

here, $\sqrt{17^2 + 1^2} = \sqrt{289 + 1} = \sqrt{290}$ ≠ 17

3)<u> Check for 20 - 3 i</u>

here, $\sqrt{20^2 + (-3)^2} = \sqrt{400 + 9} = \sqrt{409}$ ≠ 17

4) <u>Check for 4 - i</u>

here, $\sqrt{4^2 + (-1)^2} = \sqrt{16 + 1} = \sqrt{17}$ ≠ 17

Hence, none of the options are correct.

4 0

4 years ago

Which of the following is not closed under the operation being performed ?

photoshop1234 [79]

The answer is c because I checked the math on the paper.

8 0

4 years ago

Martina has a circle with a diameter

klasskru [66]

Answer:

The ratio of the circumference to its diameter remains the same.

Step-by-step explanation:

Given,

diameter of circle = 6 inch

diameter is doubled.

New diameter of circle = 2 x 6 = 12 inch

We know that,

The Circumference of a circle is 2 π r or π d where r is the radius of the circle and d is the diameter of the circle.

Circumference of the circle when the diameter is 6 inches.

C₁ = 6π

Ratio of circumference to diameter

Ratio = $\dfrac{6\pi}{6}$

Ratio = π

When the diameter is 12 inches

C₂ = 12 π

Ratio of circumference to diameter

Ratio = $\dfrac{12\pi}{12}$

Ratio = π

Now, the correct statement is the ratio of the circumference to its diameter remains the same if the diameter is doubled.

4 0

3 years ago