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3 years ago

Which statement describes a similarity between the circulatory and urinary systems?

Biology

1 answer:

Diano4ka-milaya [45]3 years ago

8 0

Answer:

Explanation:

The pulmonary system is part of the circulatory system. It helps expel carbon dioxide from the body as a waste product of cell respiration in cells. The kidneys of the urinary system on the other hand, also ‘sieve out’ metabolic waste products, especially nitrogenous waste, in the blood and expel it as urine.

The circulatory system is also significant in nourishing cells throughout the body with oxygen and nutrients. This in conjunction with the expelling of toxic metabolic waste from these cells by the urinary system play significant role in the growth and development of cells and the body at large.

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Under physiological conditions, peptide bond formation and degradation both require enzymes, but only formation requires couplin

posledela

Answer:

thermodynamically unstable but kinetically stable.

Explanation:

The complete question is as follows:

Under physiological conditions, peptide bond formation and degradation both require enzymes, but only formation requires coupling to GTP hydrolysis. Based on this information, peptide bonds under physiological conditions are:

A. both thermodynamically and kinetically stable.

B.thermodynamically unstable but kinetically stable.

C.thermodynamically stable but kinetically unstable.

D. both thermodynamically and kinetically unstable.

The term thermodynamically unstable refers to the fact that the peptide bonds are prone to breakage under physiological conditions.
The reason why one can conclude the thermodynamic instability of the peptide bonds under physiological condition is that there is a need for a source of energy i.e. GTP hydrolysis for the formation of the peptide bond.
The fact that the breakage of peptide does not require any input of energy but the only formation does confirms the fact that under physiological conditions they are thermodynamically unstable.
Even though they are thermodynamically unstable, they are kinetically stable because both the formation and degradation require enzymes.
The function of enzymes is to decrease the activation energy and hence, increase the rate of reaction. This means that if the enzymes are absent the rate of breakage of peptide bonds would be really slow this points out to the fact that they are kinetically stable under physiological conditions.

8 0

3 years ago

One gene in the human genome may be expressed at a much higher level than another. Can differences in types of cis elements pres

Oksana_A [137]

Answer:

No, CREs usually don't account for differences in gene expression levels.

Explanation:

Cis-regulatory elements (CREs) are non-coding DNA regions that regulate adjacent gene transcription. They usually do it by binding to transcription factors. They are in charge of influencing the rate of which transcription occurs, and less with how much a gene is expressed. On the other hand, trans-regulatory elements are DNA sequences that encode for upstream regulators that can modify or regulate gene expression levels.

Therefore, cis elements are not really in charge of expression levels, mostly transcription rates of single genes, rather. Trans elements are more involved in expression levels.

3 0

2 years ago

3. In a field of sugar beets in Georgia the net primary productivity is 120 grams/m^2/day, and the

konstantin123 [22]

Answer and Explanation:

Available Data:

1 gr beets = 2,000 cal

NPP = GPP – Respiration = 120 grams/m2/day

NPP= Net primary productivity of a system

GPP= Gross productivity of the producers

Respiration loss 25% of NPP

Insolation energy is 800 calories/cm2/day

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

1) Find the gross productivity of the sugar beets.

We need to calculate the GPP, which equals NPP - Respiration rate. The respiration loss is 25% of the NPP. This is:

100% NPP--------------- 120 g/m²/day

25% NPP ----------------X = (25 x 120)/100 = 30 g/m²/day

Now that we know the values of NPP and respiration rate, we can calculate the GPP.

GPP = NPP - Respiration

GPP = 120 (g/m²/day) - 30 (g/m²/day)

GPP = 90 g/m²/day

GPP = 0.009 g/cm²/day

2) Using the NPP, calculate the efficiency of photosynthesis for the sugar beets.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

We know the NPP, but this value is calculated in g/m²/day, while the Insolation energy is in g/cm²/day. We need to calculate the % Efficiency of Photosynthesis in cm. To do that, we must transform the information.

So if 1 m² = 10,000 cm², then:

10,000cm²----------120 grams/m²/day NPP

1 cm²---------------- (1 x 120) / 10,000 = 0.012 grams/cm²/day NPP

We also know that 1 gr beets = 2,000 cal, and that the Insolation energy is 800 calories/cm²/day

So we need to transform Insolation energy from calories/cm²/day to grams/cm²/day, so:

2,000 calories ----------------- 1 gr beet

800 calories/cm²/day---------X = 0.4 gr beet.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

% Efficiency of Photosynthesis = (0.012 (gr/cm2/day) /0.4 (gr/cm2/day)) X 100

% Efficiency of Photosynthesis = 3 gr/cm2/day

8 0

3 years ago

What process is similar in both fermentation and cellular respiration

gladu [14]

glycolysis in the cytoplasm is similar in both fermentation and cellular respiration.

- hope this helps

8 0

3 years ago

Read 2 more answers

What is competition what organism be competing for

lora16 [44]

Organism in an eniornment can compte for food

4 0

3 years ago