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3 years ago

Solve triangle ABC given that A=56 B=57 b=9

Mathematics

2 answers:

docker41 [41]3 years ago

7 0

Sin A/a = Sin B/b
Sin 56/a = Sin 57/9
a = (Sin 56/Sin 57) x 9
a = 8.9

c) C=67, a=8.9, c=9.88

spayn [35]3 years ago

7 0

Sin A / a = sin B / b
sin 56 / a = sin 57 / 9
a = 9sin 56 / sin 57 = 8.9

C = 180 - 56 - 57 = 67

sin 67 / c = sin 57 / 9
c = 9sin 67 / sin 57 = 9.88

option c is the correct answer.

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