24 x 0.25
6
24+6
30
so the answer is £30
Answer:
A) JK and LM will be parallel to each other.
Step-by-step explanation:
On reflection on 
line the x co-ordinate changes with y co-ordinate and y co-ordinate changes with x co-ordinate
Points on line EF
On reflection of this line on the new points we get for line JK are
Points on line GH
On reflection on y=x line the new points we get for line LM are
Slope of line JK
Slope of line LM
For two line to be parallel, their slopes will be same.
Since slopes of lines JK and LM are same therefore we can say that these are parallel to each other.
So lets get to the problem
<span>165°= 135° +30° </span>
<span>To make it easier I'm going to write the same thing like this </span>
<span>165°= 90° + 45°+30° </span>
<span>Sin165° </span>
<span>= Sin ( 90° + 45°+30° ) </span>
<span>= Cos( 45°+30° )..... (∵ Sin(90 + θ)=cosθ </span>
<span>= Cos45°Cos30° - Sin45°Sin30° </span>
<span>Cos165° </span>
<span>= Cos ( 90° + 45°+30° ) </span>
<span>= -Sin( 45°+30° )..... (∵Cos(90 + θ)=-Sinθ </span>
<span>= Sin45°Cos30° + Cos45°Sin30° </span>
<span>Tan165° </span>
<span>= Tan ( 90° + 45°+30° ) </span>
<span>= -Cot( 45°+30° )..... (∵Cot(90 + θ)=-Tanθ </span>
<span>= -1/tan(45°+30°) </span>
<span>= -[1-tan45°.Tan30°]/[tan45°+Tan30°] </span>
<span>Substitute the above values with the following... These should be memorized </span>
<span>Sin 30° = 1/2 </span>
<span>Cos 30° =[Sqrt(3)]/2 </span>
<span>Tan 30° = 1/[Sqrt(3)] </span>
<span>Sin45°=Cos45°=1/[Sqrt(2)] </span>
<span>Tan 45° = 1</span>
Answer: If i'm correct i think the subsets of b are
={0},{1},{2},{0,1},{1,2} ,{2,0},{0,1,2},{phye}
Step-by-step explanation:
