Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Answer:
idk
Step-by-step explanation:
ummmmm idkidkidkidk
In my opinion for me it looks like it could be A or B but if I am wrong then I try :(
Answer:
The formula to find the volume of a cube : s^3 so
S=40 cm
Now
by the formula,
40^3
64000