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mr Goodwill [35]
3 years ago
12

On May 1, 2021, Meta Computer, Inc., enters into a contract to sell 4,100 units of Comfort Office Keyboard to one of its clients

, Bionics, Inc., at a fixed price of $69,700, to be settled by a cash payment on May 1. Delivery is scheduled for June 1, 2021. As part of the contract, the seller offers a 25% discount coupon to Bionics for any purchases in the next six months. The seller will continue to offer a 5% discount on all sales during the same time period, which will be available to all customers. Based on experience, Meta Computer estimates a 50% probability that Bionics will redeem the 25% discount voucher, and that the coupon will be applied to $41,000 of purchases. The stand-alone selling price for the Comfort Office Keyboard is $19.00 per unit.
Business
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

Journal Entry

Explanation:

1. There are two obligations in this contract

a. keyboard

b. Customer option for future discount

2. Cash Dr,                                                     $69,700

        To Deferred revenue - keyboard                $66,215

        To Deferred revenue - discount coupon    $3,485

(Being cash is recorded)

Working note:-

Keyboards = 4,100 × $19

= $77,900

Option = $41,000 × (0.25 - 0.05) × 0.50

= $4,100

Allocation

For keyboard

= $77,900 ÷ ($77,900 + 4,100)

= 0.95

Deferred revenue Keyboard = $69,700 × 0.95

= $66,215

Option = 4,100 ÷ ($77,900 + 4,100)

= 0.05

Deferred revenue - discount coupon = $69,700 × 0.05

= $3,485

3. Cash Dr,                                                  $69,700

       To Deferred revenue Keyboard               $69,700

(Being cash is recorded)

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Consider the following linear program: Min s.t. 8X + 12Y 1X + 3Y >= 9 2X + 2Y >= 10 6X + 2Y >= 18 A, B >= 0 a. Use t
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Answer: Graph of (A) (B) and {D) are attached accordingly.

Explanation:

A)

The critical region of the constraints can be seen in the following diagram -

(0,9) (0,5) (0,3) (0,0) (3,0) (5,0) (9,0) The feasible region is shown in white

The intersection points are found by using these equations -

Vertex Lines Through Vertex Value of Objective

(3,2) x+3y = 9; 2x+2y = 10 48

(9,0) x+3y = 9; y = 0 72

(2,3) 2x+2y = 10; 6x+2y = 18 52

(0,9) 6x+2y = 18; x = 0 108

So, we can see the minimum value of the objective function occurs at point (3,2) and the minimum value of the objective function is = 48.

------------------------------------------------------------------------------------------------------------------------------------------------------------------

B)

When we change the coefficients of the variables in the objective function, the optimal solution may or may not change as the weights (coefficient) are different for each constraints for both the variabls. So, it all depends on the coefficient of the variables in the constraints.

In this case, the optimal solution does not change on changing the coefficient of X from 8 to 6 in the objective function.

The critical region would remain same (as shown below) as it is defined by the constraints and not the objective function.

(0,9) (0,5) (0,3) (0,0) (3,0) (5,0) (9,0) The feasible region is shown in white

However, the optimal value of the objective function would change as shown below-

Vertex Lines Through Vertex Value of Objective

(3,2) x+3y = 9; 2x+2y = 10 42

(9,0) x+3y = 9; y = 0 54

(2,3) 2x+2y = 10; 6x+2y = 18 48

(0,9) 6x+2y = 18; x = 0 108

So, we can see that the minimum value now has become 42 (which had to change obviously).

-------------------------------------------------------------------------------------------------------------------------------------------------------

C)

Now, when we change the coefficient of the variable Y from 12 to 6, again the critical region would remain same as earlier. But in this case, the optimal solution changes as shown below -

Vertex Lines Through Vertex Value of Objective

(3,2) x+3y = 9; 2x+2y = 10 36

(9,0) x+3y = 9; y = 0 72

(2,3) 2x+2y = 10; 6x+2y = 18 34

(0,9) 6x+2y = 18; x = 0 54

We can see that the minimum value now occurs at (2,3) which is 34, so both the optimal solution and optimal value have changed in this case.

----------------------------------------------------------------------------------------------------------------------------------------------------------

D)

When we limit the range of the variables as -

4 \leq X \leq 8 \:\: and\:\: 12\leq Y \leq 24,

the critical region now becomes -

So, the new critical points are (4,12), (4,24), (8,24) and (8,12).

So, the values of the objective function at these points can be calculated as -

Vertex Value of Objective

(4,12) 8*4+12*12 = 176

(4,24) 8*4+12*24 = 320

(8,24) 8*8+12*24 = 352

(8,12) 8*8+12*12 = 208

So, the new optimal solution is (4,12) and the optimal value is 176.

if we knew the range of the variables in the part B and C earlier, we could have just said that the optimal solution will not change as the value would have been no longer depended on the coefficients of variables in the constraints.

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