Figure this out as though no digits are present. You can choose 8 of the 26 letters and that's it.
26^8 [you can allow repeating letters] = 2.088 * 10^11
The total number of ways that can be chosen with letters and digits intermixed = 36^8
The probability of getting no numbers is 26^8 / 36^8 or (26/36)^8 = 0.07402
So the probability that there were be at least one digit is
1 - 0.07402 = 0.92598
Answer:
a=4
Step-by-step explanation:
Answer:
The change to the face 3 affects the value of P(Odd Number)
Step-by-step explanation:
Analysing the question one statement at a time.
Before the face with 3 is loaded to be twice likely to come up.
The sample space is:

And the probability of each is:








P(Odd Number) is then calculated as:


Take LCM



After the face with 3 is loaded to be twice likely to come up.
The sample space becomes:

The probability of each is:








Take LCM


Comparing P(Odd Number) before and after
--- Before
--- After
<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>
Answer:
m=9
Step-by-step explanation:
11-9m=-70
-11 -11
-9m = -81
divide both sides by -9 and you get m=9
Easy ill tell u and then do a equation first sense it has - it means u have to subtract alright it goes like this. 17,1
9,3
--------
7,8
and this is ur answer as u see in my equation ur welcome only give me brainiest only if im right