Well. I can't see the picture. But it would be decreasing at a rate of 4 so pick a point on the any line move over to the right one, then down four. And for the y intercept the line would intersect the y axis at positive one. Sorry if that's confusing
The answer is 90%. You get this answer by multiplying both the numerator and denominator by 5 so 18x5=90 and 20x5=100 giving you a fraction of 90/100 and a percentage of 90%.
Correct Question:
Otero translated the phrase "three less than a number" into the expression 3 minus x. Which best describes the accuracy of Otero's expression?.
a. It is accurate. The phrase can be translated as "three" = 3, "less than" = subtraction, and "a number" = X, SO 3- X is
the correct expression.
b. It is inaccurate. Three is being subtracted from a number, so X-3 is what he should have written.
c. It is inaccurate. Three is being compared to a number, so 3 It is inaccurate. Three is being added to a number, so 3+ x is what he should have written.
Answer:
The answer is B because three less than a number means that a 3 is less than some number X meaning three is being subtracted from X. So equation should be X-3 rather than 3-X.
Step-by-step explanation:
Answer:
A) 150 m
B) 180.28 m
Step-by-step explanation:
A) In order to find the horizontal distance from the base of the cliff to the speed boat, use the Pythagorean theorem to calculate the length of the missing side.
We are told that one of the sides is 80 m and the hypotenuse is 170 m. Therefore,
- a² + b² = c²
- (80)² + b² = (170)²
- b² = 170² - 80²
- b² = 22500
- b = 150
The horizontal distance between the base of the cliff and the boat is 150 m.
B) Now, the side that was 80 m is now 100 m (includes the height that the helicopter is above Jumbo). The horizontal distance remains the same, 150 m, but the hypotenuse is different. Solving for the hypotenuse will give us the distance between the helicopter and the speed boat.
- (100)² + (150)² = c²
- 32500 = c²
- 180.28 = c
The distance between the helicopter and the speed boat is 180.28 m.
