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2 years ago

8

Which of the following algebraic expressions represents the statement given below?

1 answer:

viva [34]2 years ago

7 0

From the given problem above, the correct answer would be the last option since it stated that a number which is X is increased by five or added by five and then the sum is then squared. Therefore, it is option D. (X+5)^2.

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What is the difference between 0.0032 and 0.32? and which one is greater?

mariarad [96]

.0032 = 0.32%
.32 = 32%
.32 is 100 times greater than .0032, therefore, 0.32 is greater

8 0

3 years ago

Read 2 more answers

Please help me....I really need help!!

scoundrel [369]

$\dfrac{c^2-4}{6c^4+15c^3}\div\dfrac{c^2+4c+4}{12c^3+30c^2}=\dfrac{c^2-2^2}{3c^3(2c+5)}\div\dfrac{c^2+2(c)(2)+2^2}{6c^2(2c+5)}\\\\_{\text{use}\ a^2-b^2=(a-b)(a+b)\ \text{and}\ (a+b)^2=a^2+2ab+b^2}\\\\=\dfrac{(c-2)(c+2)}{3c^3(2c+5)}\cdot\dfrac{6c^2(2c+5)}{(c+2)^2}=\dfrac{(c-2)}{c}\cdot\dfrac{2}{(c+2)}=\boxed{\dfrac{2(c-2)}{c(c+2)}}$

6 0

3 years ago

What is the volume of a rectangular prism with side lengths of x, x +4, and 2x-1

marysya [2.9K]

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6 0

3 years ago

sweet [91]

Answer:

20%

Step-by-step explanation:

Step 1: Subtract starting value minus the final value (decrease)

$\$5.75 - \$4.60\\\\= 5.75 - 4.60 \\\\= 1.15$

Step 2: Divide the decrease by the original number

$1.15 \div 5.75\\\\= \frac{1.15}{5.75}\\\\= 0.2$

Step 3: Multiply the result by 100 to get a percent decrease

$0.2 \times 100\\\\= 20$

Therefore, the percent decrease of the price of paper per package is 20%

<em>Note: If the percentage is negative, it means there was an increase and not a decrease.</em>

3 0

2 years ago

PLZ HELP ME NEED THIS FAST WILL GIVE BRAINLIEST

OleMash [197]

Answer: l = 60 ft and w = 30 ft

P = 2(l + w)

180 = 2(l + w)

Let x = width of his yard

Let 2x = length of his yard

$180=2(2x+x)$

$\frac{180}{2}=\frac{2(2x+x)}{2}$

$90=3x$

$\frac{90}{3} =\frac{3x}{3}$

$x=30ft$

l = 2x = 30(2) = 60 ft

Check:

180 = 2(l + w)

180 = 2(60 + 30)

180 = 2(90)

180 = 180

LS = RS

4 0

3 years ago