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amid [387]
2 years ago
8

Which of the following algebraic expressions represents the statement given below?

Mathematics
1 answer:
viva [34]2 years ago
7 0
From the given problem above, the correct answer would be the last option since it stated that a number which is X is increased by five or added by five and then the sum is then squared. Therefore, it is option D. (X+5)^2. 
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Please help me!! Question is on the image
Flura [38]

Answer:

42

Step-by-step explanation:

8+8+12+4+4+3+3

Something like this for the problem.

4 0
3 years ago
Solve for j.<br> j/-2+7=-12<br> j=
tangare [24]
J/-2 + 7 = -12 multiply both sides with 2

-j + 14 = -24 move -14 to the other side and change sign

-j= -24 - 14
-j = -38 and if you divide -38 with -1 you get + 38
j=38




4 0
3 years ago
HELP PLEASE I NEED THIS FOR GRADUATION
Alexxandr [17]
√324 * √75 = √24300 = 90√3
so
90√3 / 9 = 10√3

answer is
D. last one 10√3 irrational
8 0
3 years ago
What is the median for 76,84,93,67,82,and 76
Lapatulllka [165]
First arrange the numbers from least to greatest:

67, 76, 76, 82, 84, 93

The median is the middle number. But since we have two numbers that are in the middle we have to find the average of them.

76 + 82 = 158
158/2 = 79

So your answer is 79
3 0
3 years ago
Read 2 more answers
Tesla Battery Recharge Time.The electric­ vehicle manufacturing company Tesla esti­mates that a driver who commutes 50 miles per
madam [21]

Answer:

a.) f(x) = \frac{1}{30} where 90 < x < 120

b.) \frac{2}{3}

c.)  \frac{2}{3}

d.)  \frac{1}{2}

Step-by-step explanation:

Let

X be a uniform random variable that denotes the actual charging time of battery.

Given that, the actual recharging time required is uniformly distributed between 90 and 120 minutes.

⇒X ≈ ∪ ( 90, 120 )

a.)

Probability density function , f (x) = \frac{1}{120 - 90} = \frac{1}{30} where 90 < x < 120

b.)

P(x < 110) = \int\limits^{110}_{90} {\frac{1}{30} } \, dx

               = \frac{1}{30}[x]\limits^{110}_{90}  = \frac{1}{30} [ 110 - 90 ] = \frac{1}{30} [ 20] = \frac{2}{3}

c.)

P(x > 100 ) = \int\limits^{120}_{100} {\frac{1}{30} } \, dx

                 = \frac{1}{30}[x]\limits^{120}_{100}  = \frac{1}{30} [ 120 - 100 ] = \frac{1}{30} [ 20] = \frac{2}{3}

d.)

P(95 < x< 110)  = \int\limits^{110}_{95} {\frac{1}{30} } \, dx

                       = \frac{1}{30}[x]\limits^{110}_{95}  = \frac{1}{30} [ 110 - 95 ] = \frac{1}{30} [ 15] = \frac{1}{2}

7 0
3 years ago
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