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inn [45]
3 years ago
14

If line s and line t are parallel lines cut by transversal line r, what is the value of x?

Mathematics
1 answer:
RideAnS [48]3 years ago
6 0

Answer:

Because s and t are parallel x=12

Step-by-step explanation:

To get this you have to solve for (4x-12)+120=180 solve for x

4x+12=60

4x=48

=12

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Peaches are on sale for 0.95 cents per pounds if i have 2.75 pounds how much did i pay for the peaches?
Dennis_Churaev [7]

Answer:

$2.61

Step-by-step explanation:

I think you mean 0.95 dollars per pound. 0.95 cents means it's less than a dime per pound.

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3 years ago
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18. During a sale, cameras were discounted 30% from their original price of $295.99. How much was each camera during the sale to
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Answer:

207.19 is the cost on sale

Step-by-step explanation:

If there is a discount of 30%, we still have to pay 100-30 = 70%

295.99 * 70%

295.99 * .70

207.193

Rounding to the nearest cent

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Which of these triangle pairs can be mapped to each other using a reflection
tia_tia [17]
Help me! I’ll mark you brainly!
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3 years ago
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.
Aleks [24]

Answer:

A.) 24.08 seconds

B.) 825.42 metres

Step-by-step explanation:

function of time is given as

h ( t ) = − 4.9 t 2 + 118 t + 115 .

Where a = -4.9, b = 118, c = 115

Let's assume that the trajectory of the rocket is a perfect parabola.

The time t the rocket will reach its maximum height will be at the symmetry of the parabola.

t = -b/2a

Substitute b and a into the formula

t = -118/-2(4.9)

t = 118/9.8

t = 12.041 seconds

Since NASA launches the rocket at t = 0 seconds, the time it will splash down into the ocean will be 2t.

2t = 2 × 12.041 = 24.08 seconds

Therefore, the rocket splashes down after 24.08 seconds.

B.) At maximum height, time t = 12.041s

Substitute t for 12.041 in the function

h ( t ) = − 4.9 t 2 + 118 t + 115

h(t) = -4.9(12.041)^2 + 118(12.041) + 115

h(t) = -4.9(144.98) + 118(12.041) + 115

h(t) = -710.402 + 1420.82 + 115

h(t) = 825.42 metres

Therefore, the rocket get to the peak at 825.42 metres

6 0
3 years ago
If the length of segment AC equals 58, what is the length of the midsegment DE
Delicious77 [7]

Answer:

B) 29

Step-by-step explanation:

Given:

AC= 58

Point D and E are the midpoints of side AB and BC Respectively.

Solution:

According to Midpoint theorem which states:

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DE= \frac{58}{2} =29

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3 years ago
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