6.5 x 1/9 please help
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The surface area of the cylinder that forms the "sides" of the microvillus rod is given by the area of the curved surface of a cylinder with diameter (d) = 0.1 μm and height (h) = <span>1.0 μm.
The curved surface area of a cylinder is given by 2πrh, where r = d / 2 = 0.1 / 2 = 0.05 </span><span>μm.
Thus, the curved surface area is given by
Therefore, </span>the surface area of the cylinder that forms the "sides" of the microvillus rod is
The curved surface area of a cylinder is given by 2πrh, where r = d / 2 = 0.1 / 2 = 0.05 </span><span>μm.
Thus, the curved surface area is given by
Therefore, </span>the surface area of the cylinder that forms the "sides" of the microvillus rod is