3 years ago

Can yall plz help!!!

Mathematics

1 answer:

lesya692 [45]3 years ago

4 0

Number one would be -8

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You are graphing Square ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the square: A(4,

Kitty [74]

Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

The diagonals are BD and AC

Midpoint of BD = Midpoint of AC

$\left(\dfrac{8+x}{2},\dfrac{-7+y}{2}\right) =\left(\dfrac{4+8}{2},\dfrac{-7+(-3)}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(\dfrac{12}{2},\dfrac{-10}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(6,-5\right)\\$Therefore$:\\\dfrac{8+x}{2}=6\\8+x=12\\x=12-8\\x=4\\$Similarly$\\\dfrac{y-7}{2}=-5\\y-7=-5*2\\y-7=-10\\y=-10+7=-3$

The coordinates of the fourth vertex is D(4,-3)

3 0

3 years ago

How do you do this ? Anyone who know how and can explain this

Murrr4er [49]

Answer:

G. 105.

Step-by-step explanation:

Percentage of cars with 3 or more people

= 15 + 7 + 3

= 25%,

25% of 420

= 0.25 * 420

= 105.

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2 years ago

The graph of a quadratic function passes through the points (-1,0), (-2,0), and (0,2). Write the quadratic function in general f

tatuchka [14]

Answer:

Step-by-step explanation:

You have 3 points and need to find ax2 + bx + c = y. First use (0,2). x is zero, so y = 2 = c. You have c. Now put (-1,0) into the equation. 0 = 1a -b + 2. Rearrange so you get b = a + 2. Now use the other point. a*(-2 squared) + b*(-2) + 2 = 0. Simplify and substitute (a + 2) for b and you will have the answer.

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3 years ago

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tigry1 [53]

Answer:

Step-by-step explanation:

Have a good day. ;-)

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3 years ago

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