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BARSIC [14]
4 years ago
11

Can yall plz help!!!

Mathematics
1 answer:
lesya692 [45]4 years ago
4 0

Number one would be -8

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Simply round the result to an appropriate value (e.g. 3 decimal places).

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<span>Assuming that the particle is the 3rd particle, we know that it’s location must be beyond q2; it cannot be between q1 and q2 since both fields point the similar way in the between region (due to attraction). Choosing an arbitrary value of 1 for L, we get </span>

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3 0
3 years ago
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Answer:

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Step-by-step explanation:

The best way to go about this is to use a trig identity. You have the unknown opposite the angle and the hypotenuse, so its best to use the sine identity: sin(x)=\frac{O}{H}, where O is the opposite side, and H is the hypotenuse.

Set up the equation as:sin(27)=\frac{x}{17}, and solve for X.

I got x=7.718, rounded to x=8.

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Answer:

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