Can yall plz help!!!

PLS HELP W ANGLE OF ISOLATION ILL GIVE BRAINLIEST I NEED ANSWER WITHIN 5 MINS

zlopas [31]

45 so the sun can hit directly to the panel

5 0

3 years ago

Read 2 more answers

HELP PLEASE

Fantom [35]

Answer:

Option C

Step-by-step explanation:

You forgot to attach the expression that models the cost of the camping trip during the three days. However, by analyzing the units, the answer can be reached.

The total cost has to be in units of $.

There are two types of costs in the problem:

Those that depend on the number of days ($/day )

Those that depend on the number of students and the number of days ($/(student * day))

If there are 3 days of camping and b students, then you have to multiply the costs that depend on the days by the number of days (3), and the costs that depend on the number of students you have to multiply them by 'b'

So, if the costs that must be multiplied by 'b' are only those that depend on the number of students, the coefficient of b must be:

3 days (Cost of training + Cost of food Miscellaneous expenses :).

Therefore the correct answer is option C:

C. It is the total cost of 3 days per student of Mr. Brown, with training, food and miscellaneous expenses.

The expression that represents the total expense should have a formula similar to this:

$y = (3 days) *([\frac{20.dollars}{(day * student)} + \frac{30.dollars}{(student * day)} + \frac{50.dollars}{(student * day)}] b + \frac{200}{day}) + 1050.dollars$

y = 3 ($ 100b + $ 200) + $ 1050

3 0

3 years ago

Read 2 more answers

A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha

White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

$\frac{dB}{dt} = rB-k$

$\Rightarrow \frac{dB}{dt} - rB=-k$ .......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor $=e^{\int p(t) dt$

$=e^{\int (-r)dt$

$=e^{-rt}$

Multiplying the integrating factor the both sides of equation (1)

$e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}$

$\Rightarrow e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt$

Integrating both sides

$\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt$

$\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C$ [ where C arbitrary constant]

$\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}$

Initial condition B=7864 when t =0

$\therefore 7864= \frac{k}{r} - Ce^0$

$\Rightarrow C= \frac{k}{r} -7864$

Then the general solution is

$B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}$

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

$B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}$

$\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0$

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

=$1573.17

4 0

4 years ago

Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has

Feliz [49]

Answer:

16 sweets

Step-by-step explanation:

Number of sweet that Sekhar had = x

Sweets given to Renu = (1/4) of x = $\frac{1}{4}x$

Sweets given to Raji = 5

Remaining sweets = 7

$x = \frac{1}{4}x +5 + 7\\\\x -\frac{1}{4}x = 12\\\\\frac{4*x}{1*4}x-\frac{1}{4}x = 12\\\\\frac{4x}{4}-\frac{1}{4}x= 12\\\\\frac{3x}{4}=12\\\\x = 12*\frac{4}{3}\\\\x=4*4\\\\x=16$

6 0

3 years ago

it costs $20 for 4 play tickets and $35 for 7 play tickets. Is cost per ticket constant? why or why not?

KonstantinChe [14]

Answer:

The cost per ticket is<u> constant</u>.

Step-by-step explanation:

Given:

It costs $20 for 4 play tickets and $35 for 7 play tickets.

Now, to get whether cost per ticket is constant or not.

So, if the cost per ticket is constant that means the cost of ticket for a play or more is fixed, non-varying and it does not change.

Now, we check it:

4 play tickets costs = $20.

1 play tickets costs = $20 ÷ 4 = $5.

So, 7 play tickets costs = $5 × 7 = $35.

Thus, the cost of ticket for play is not changing and it is constant.

So the cost per ticket is constant.

Therefore, the cost per ticket is constant.

4 0

3 years ago