When finding the domain of a square root, you have to know that it is impossible to get the square root of 0 or any negative number. since domain is possible x values this means that x cannot be 0 or any number less than 0. However, you can find the square root of the smallest most infinitely small number greater than 0. since an infinitely small number close to zero can not be written out, we must must say that the domain starts at 0 exclusive. exclusive is represented by an open or close parenthesis so in this case the domain starts with:
(0,
we can get the square root of any number larger than 0 up to infinity but infinity can never be reached so it is also exclusive. So so the ending of our domain would be:
,infinity)
So the answer if the square root is only over the x the answer is
(0, infinity)
But if the square root is over the x- 5 then this would brIng a smaller amount of possible x values. since anything under the square root sign has to be greater than 0, you can say that:
(x - 5) > 0
x > 5
Therefore the domain would start at 5 and the answer would be:
(5, infinity)
Answer:
Option A is correct .
Step-by-step explanation:
if in a question it is given that BC is equal to AB then only we can do like that...
What the question and what the picture
Answer:
The inverse is ±sqrt(x/6)
Step-by-step explanation:
Let y = 6x^2
To find the inverse, exchange x and y and then solve for y
Exchange x and y
x = 6y^2
Solve for y
Divide each side by 6
x/6 = 6y^2 /6
x/6 = y^2
Take the square root of each side
±sqrt(x/6) = sqrt(y^2)
±sqrt(x/6) =y
The inverse is ±sqrt(x/6)
