The given question is incomplete as the option are not provided however, the correct options are as follows:
Defective proteins are often degraded quickly, making their effects temporary.
Single amino acid substitutions caused by errors in mRNA transcription would not affect protein function.
Unlike DNA mutations, mRNA transcripts have short half-lives and are not inherited across many generations.
Degradation of defective proteins activates mRNA repair pathways RNA polymerases synthesize many transcripts per gene, so only a small fraction of RNA transcripts would have errors.
ch mRNA molecule is only translated once and then degraded
Answer:
The correct answer is - statements 1, 3, and 4.
Explanation:
DNA polymerase is the enzyme that is responsible for the production of the new DNA molecule and any mutation in this enzyme that will inhibit the DNA repair process which affects future generations.
RNA polymerase is an enzyme that is responsible for the transcription of DNA to mRNA and any error-prone mRNAs have chances of degradation. Error in DNA replication is from generation to generation as it is inherited
The process of transcription is quick.
Answer: sponges are the cleaners of the water around the corals , coral feeders , and healers in a sens
Explanation:
approximately 115 days
Human red blood cells (RBC), after differentiating from erythroblasts in the bone marrow, are released into the blood and survive in the circulation for approximately 115 days.
Answer:
Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).
Explanation:
<u>Datos disponibles:</u>
- Cruce entre peces naranjas y peces grises
- 50% de la F1 son peces grises
- Naranja dominante sobre gris
Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo para color gris <em>n</em>.
Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.
Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.
Cruce:
Parental) Nn x nn
Gametas) N n n n
Fenotipos) Naranja Gris
Cuadro de Punnett) N n
n Nn nn
n Nn nn
F1) 2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn
2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,
nn
50% de la progenie será color naranja (Nn)
50% de la progenie será color gris (nn)
Answer:
what scenario, nothing is there
