When a BB male and a Bb female are crossed, 50% BB and 50% Bb genotypes are produced and a 100% black phenotype.
The entire number of genes that an organism receives from its parents makes up its genotype. Alleles, which are pairs of these genes, are found. One gene is dominant and one gene is recessive in each allele.
The dominant gene is always expressed in a cross if it is present. Only when a pair of alleles is made up of two recessive genes does the recessive gene express itself. In this instance, the white fur is subordinate to the black fur. White fur is represented as b, while black fur is represented as B.
We can see that when we cross the BB male and Bb female, we will get a genotype that is 50% BB and 50% Bb, as well as a phenotype that is 100% black fur.
Parents: BB x Bb
Gametes: B, B, and B, b
Offspring: BB, BB, Bb, Bb
The genotypic ratio = 1:1
The phenotypic ratio = 1:0
Genotype probabilities:
P(BB) = 2/4 = 0.5 or 50%
P(Bb) = 2/4 = 0.5 or 50%
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4 is the correct answer hope you get it right!!!
Because it helps us understand our past, which in turn allows us to understand our present.
Answer:
the external oblique.
Explanation:
<u>the external oblique</u> covers the ventral, abdominal region in rats.
Answer:
Steps to cellular respiration:
1) In the first step of respiration, glycolysis occurs in which glucose molecule is converted into pyruvate molecule.
2) Krebs cycle is also called citric acidity cycle. In this cycle, hydrogen and electron are produced from the oxidation of pyruvate molecule and provides to electron transport chain.
3) Electrons carried by NADH + H and FADH2 are converted into oxygen through a series of electron carriers, and production of ATP occurs.
