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AfilCa [17]
2 years ago
7

Which polynomial function has a root of 1 with multiplicity 2 and a root of 6 with multiplicity 1

Mathematics
2 answers:
Mashutka [201]2 years ago
7 0

Answer:

f(x)=x^3-8x^2+13x-6

Step-by-step explanation:

We are given information about polynomial as

a root of 1 with multiplicity 2

so, one of factor is (x-1)^2

a root of 6 with multiplicity 1

so, another factor is (x-6)^2

so, we can write polynomial as

f(x)=(x-1)^2(x-6)

now, we can simplify it

f(x)=(x-1)(x-1)(x-6)

f(x)=(x^2-2x+1)(x-6)

So, we get polynomial as

f(x)=x^3-8x^2+13x-6

aleksley [76]2 years ago
6 0

Answer: f(x) = (x – 1)(x – 1)(x – 6)

Step-by-step explanation:

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