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Veronika [31]
3 years ago
12

GIven f(x) = 3x + 2, Find f(x) = 8 (Solve for x)

Mathematics
1 answer:
vodomira [7]3 years ago
8 0
F(x)=8
3x+2=8
-2 both sides
3x=6
Divide 3 both sides
X=6/3
X=2
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Determine the slope-intercept form of the equation of the line parallel to y = -4/3 x + 11 that passes through the point (–6, 2)
rewona [7]

Answer: -4/3x - 6

Step-by-step explanation:

First, let's find the slope of the line

y=- -4/3x+11

As the equation is already in slope-intercept form y=mx+c ,

Slope = -4/3

Let a point (x,y) be on the new line.

By finding the slope again,

y−2/x+6= -4/3

y−2= -4/3(x+6)

y−2= -4/3x−8

y = -4/3x - 6

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3 years ago
The matrices shows the number of dance students enrolled in each type of class for two different years.
Scorpion4ik [409]

Answer:

n54

Step-by-step explanation:

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3 years ago
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A number decreased by 7 is at most 13
maxonik [38]
X-7 < (or equal to) 13
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3 years ago
The function f(x) is shown on the graph.
Sever21 [200]

The value of f(0) is 12.

<h3>What is graph?</h3>

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

By considering the graph we have to find f(0) which means we have to find that point where x- coordinate is zero.

Also, which shows that 12 the function f(x)

So, taking the point is (0,12) we can get f(0)= 12.

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7 0
2 years ago
If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by​
PIT_PIT [208]

Answer:

The family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|} (1)

Where:

\theta - Angle between vectors, in sexagesimal degrees.

\|\vec a\|, \|\vec b \| - Norms of vectors \vec {a} and \vec{b}

If \theta is acute, then the cosine function is bounded between 0 a 1 and if we know that \vec {a} = (p, 3, -7) and \vec {b} = (p, -p, 4), then the possible values for p are:

Minimum (\cos \theta = 0)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0

Maximum (\cos \theta = 1)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1

With the help of a graphing tool we get the family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

7 0
3 years ago
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